Consider these two crosses and assume that independent segregation is exhibited by all gene pairs: RrmmTT x RRMmTt FfGg x FfGg Derive the gametic ratio of the second parent in each cross using the branching method. What proportion of the offspring in each cross will be heterozygous for all gene pairs? Derive the genotypic ratio for the offspring from each cross using the branching method.
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Consider these two crosses and assume that independent segregation is exhibited by all gene pairs:
RrmmTT x RRMmTt
FfGg x FfGg
- Derive the gametic ratio of the second parent in each cross using the branching method.
- What proportion of the offspring in each cross will be heterozygous for all gene pairs?
- Derive the genotypic ratio for the offspring from each cross using the branching method.
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- Consider these two crosses and assume that independent segregation is exhibited by all gene pairs. Derive the gametic ratio of the second parent in each cross using the branching method. What proportion of the offspring in each cross will be heterozygous for all gene pairs? Derive the genotypic ratio for the offspring from each cross using the branching method. Show complete solutions. a. RrmmTT x RRMmTtb. FfGg x FfGgWhat are the expected phenotypic ratios from the following cross:Tt Rr yy Aa × Tt rr YY Aa, where T = tall, t = dwarf, R = round,r = wrinkled, Y = yellow, y = green, A = axial, a = terminal; T, R,Y, and A are dominant alleles. Note: Consider using the multiplication method in answering this problemConsider the cross RrmmTT x RRMmTt. Assume the three gene pairs are independently segregating. a. Derive the gametic ratio of the second parent using the branching method.b. Derive the genotypic ratio for the offspring from each cross using the branching method. Showcomplete solutions.c. What is the probability that an offspring from this cross will be heterozygous for all gene pairs?
- In the following cross, imagine that you have a female fly that has two Xs and one Y due to a nondisjunction event in her mother's germ cells. Draw out what the possible gametes are for both the female and the male and also a Punnett square showing the genotypes, phenotypes, and sex of the possible flies as a result of this cross. You do not need to provide the probabilities of each of these. Red-eyed wi C Ở Red-eyed wt XX Y X Y MeiosisAssume that the trihybrid cross AABBrr x aabbRR is made in a plant species. Assume that A and B are dominant alleles, but there is no dominance effect of alleles at the R locus. a) How many different gametes are possible in the F1generation? What are the genotypes of these gametes? b) What is the probability of the parental aabbRR genotype in the F2 progeny? c) What proportion of the F2 progeny would be expected to be homozygous for all three genes?Table 2 below shows the banding pattern for a cross between parents P1 and P2 producing the 6 progeny I1-6. The parents are double heterozygotes for two independently assorting genes. Identify the pairs of bands that correspond to the two segregating pairs of alleles. Assuming independent assortment, what is the probability that an offspring shows the pattern observed in I5. Table 2 RFLP data Size (kb) P1 P2 I1 I2 I3 I4 I5 I6 5.5 X X X X X X 3.5 X X X X X X X 2.5 X X X X X 2 X X X X X
- Use the forkline method to derive the gametic ratio of cross AabbDD x AABbDd. The cross are segregated independently.A series of three-point testcrosses is made to determine the genetic map order of seven linked allele pairs: A/a, B/b, G/g, H/h, Q/q, R/r, and Y/y.From each cross between a triply heterozygous parent listed below, two recombinant classes were noticed as the least frequent among all 8 progeny classes, and are listed at the right in the table. A. For each testcross write the genotype of the F1 heterozygous parent. F1 Parental Phenotype Least frequent F2 Phenotype 1.AHB&ahb AHb & ahB 2.RYh&ryH RYH & ryh 3.BhY&bHy Bhy & bHY 4.qYB&Qyb qYb & QyB 5.AbQ&aBq Abq & aBQ 6.ghR&GHr ghr & GHR B. Write the unified map order of these genes, showing your reasoning.A trihybrid individual with the genotype QqRrTt is testcrossed with a ggrrtt individual. The resulting offspring are as follows: QrT QRt Qrt 11 grT 76 50 qRT 357 343 qrt 78 QRT 76 qRt Total = 1000 Determine the allele arrangement and gene order in the trihybrid parent. Give your answer using the AbC/aBc notation. Draw a chromosome map for these genes. Give your map distances to one decimal place. (Use underline or underscore (_) to draw the line for the map) a) b)
- In onion, male sterility is produced when the nuclear genotype is aa and the mitochondrial gene S (sterile) are present. Any other combination of nuclear genotype and mitochondrial gene (including gene F for fertile) will result in a male fertile plant. Give the genotypic ratio and the phenotypic ratio or the percentage of male sterile and male fertile offspring that will be produced in the following crosses. 1. Aa + S male x aa + F female 2. Reciprocal cross of number 1. (Note that when we do reciprocal cross, we interchange/swap the genotypes of the parents (if there is a nuclear gene involved, you interchange the nuclear genotype as well). 3. Aa + S female x Aa + F male 4. Reciprocal cross of number 3.The genotypes of F1 individuals in a trihybrid cross are LlMMNn x llMmNn. What is the probability that the F2 offspring will have an LlMmnn genotype? Use the forked-line method in solving the problem.The following two genotypes are crossed: AaBbCcX+X x AaBBCCX+Y, where a, b, and c represent autosomal genes and X and X' represent X-linked alleles in an organism with XY sex determination. What is the probability of obtaining genotype AaBBCCX+X+? Additionally, what must we assume about these genes to calculate probability? 1/16, assume all genes are located on the same chromosome 1/64, assume all genes are located on the same chromosome O 1/32, assume all genes are located on the same chromosome 1/32, assume genes assort independently 1/16, assume genes assort independently 1/64, assume genes assort independently