Consider the following linked list C++ code: - struct node { int data; struct node *next; }start = NULL; struct node *new_node; Select one: a. new_node=(struct node *)malloc(sizeof(struct node)); b. Non of Above с. new_node=(struct node)malloc(sizeof(struct node)); new_node=(struct *)malloc(sizeof(struct node)); d. new_node=(struct node *)malloc((struct node));

Consider the following linked list C++ code: - struct node { int data; struct node next; }start = NULL; struct node new_node; Select one: a. new_node=(struct node )malloc(sizeof(struct node)); b. Non of Above с. new_node=(struct node)malloc(sizeof(struct node)); new_node=(struct )malloc(sizeof(struct node)); d. new_node=(struct node *)malloc((struct node));

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#ifndef LLCP_INT_H#define LLCP_INT_H #include <iostream> struct Node{ int data; Node *link;}; bool DelOddCopEven(Node* headPtr);int FindListLength(Node* headPtr);bool IsSortedUp(Node* headPtr);void InsertAsHead(Node*& headPtr, int value);void InsertAsTail(Node*& headPtr, int value);void InsertSortedUp(Node*& headPtr, int value);bool DelFirstTargetNode(Node*& headPtr, int target);bool DelNodeBefore1stMatch(Node*& headPtr, int target);void ShowAll(std::ostream& outs, Node* headPtr);void FindMinMax(Node* headPtr, int& minValue, int& maxValue);double FindAverage(Node* headPtr);void ListClear(Node*& headPtr, int noMsg = 0); // prototype of DelOddCopEven of Assignment 5 Part 1 #endif // definition of DelOddCopEven of Assignment 5 Part 1//Algorithm should: /*NOT destroy any of the originally even-valued node. This means that the originally even-valued nodes should be retained as part of the resulting list. Destroy…
#ifndef LLCP_INT_H#define LLCP_INT_H #include <iostream> struct Node{ int data; Node *link;};void DelOddCopEven(Node*& headPtr);int FindListLength(Node* headPtr);bool IsSortedUp(Node* headPtr);void InsertAsHead(Node*& headPtr, int value);void InsertAsTail(Node*& headPtr, int value);void InsertSortedUp(Node*& headPtr, int value);bool DelFirstTargetNode(Node*& headPtr, int target);bool DelNodeBefore1stMatch(Node*& headPtr, int target);void ShowAll(std::ostream& outs, Node* headPtr);void FindMinMax(Node* headPtr, int& minValue, int& maxValue);double FindAverage(Node* headPtr);void ListClear(Node*& headPtr, int noMsg = 0); // prototype of DelOddCopEven of Assignment 5 Part 1 #endif
The definition of linked list is given as follows: struct Node { ElementType Element ; struct Node *Next ; } ; typedef struct Node *PtrToNode, *List, *Position; If L is head pointer of a linked list, then the data type of L should be ??
Multiple choice in data structures void doo(node<int>*root){ if(root !=0) { node<int>*p=root; while(root->next!=0) root=root->next; p->data=root->data; } What is this code do? a. swap the first item with the last item in the linked list b. set the first item in the linked list as the last item c. doesn't do anything because the root parameter is passed by value d. change the root item in the binary tree with the farthest leaf item
1. Start with analysing the problem by using a flowchart/pseudo code. 2. As mention above, build a C++ program based on the appropriate method/function. You are free to create your own menu and display. Consider the following case: You have been appointed as a teacher of 3 Gemilang class in SMK Tanjung Malim. Please create a program that can keep the name list of your students in the class. The list must consist of two lists, first list is for all female student's names and the second list is for all male student's names. You must also provide the list of all the student's name. In order to do that, you need to merge both of the list together. The name in the list needs to be sorted alphabetically. The program must consist of the following method function: a) menu() – as interface for the user b) add list(string) – to add name to the list c) sort list() – to sort the name in the list d) show list) – to display the lists e) search list(string) – to search a name in the list ) merge…
Given the following C code: struct Node int data: struct Node* prev: struct Node next: Which one of following statements delete the node pointed by X? (Assume that X does not point to head or tail of the linked list) a) X->prev->next-x->prev; X->next->prev-X->next: b) X->prev->prev-X->next; c) X->prev->next-X->next: d) X->prev->prev-X->prev: X->next->next-X->prev: X->next->prev-X->prev; X->next->next-X->next:
1, Build a C++ program based on the appropriate method/function. You are free to create your own menu and display. Consider the following case: You have been appointed as a teacher of 3 Gemilang class in SMK Tanjung Malim. Please create a program that can keep the name list of your students in the class. The list must consist of two lists, first list is for all female student's names and the second list is for all male student's names. You must also provide the list of all the student's name. In order to do that, you need to merge both of the list together. The name in the list needs to be sorted alphabetically. The program must consist of the following method function: a) menu() – as interface for the user b) add_list(string) – to add name to the list c) sort_list() – to sort the name in the list d) show_list() – to display the lists e) search_list(string) – to search a name in the list f) merge_list(list1, list2) – to display list of students name (merge list) g) delete_list() – to…
struct remove_from_front_of_dll { // Function takes no parameters, removes the book at the front of a doubly // linked list, and returns nothing. void operator()(const Book& unused) { //// TO-DO (13) |||| // Write the lines of code to remove the book at the front of "my_dll", // // Remember, attempting to remove an element from an empty data structure is // a logic error. Include code to avoid that. ///// END-TO-DO (13) //// } std::list& my_dll; };
C++ ProgrammingActivity: Queue Linked List Explain the flow of the code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow. #include "queue.h" #include "linkedlist.h" class SLLQueue : public Queue { LinkedList* list; public: SLLQueue() { list = new LinkedList(); } void enqueue(int e) { list->addTail(e); return; } int dequeue() { int elem; elem = list->removeHead(); return elem; } int first() { int elem; elem = list->get(1); return elem;; } int size() { return list->size(); } bool isEmpty() { return list->isEmpty(); } int collect(int max) { int sum = 0; while(first() != 0) { if(sum + first() <= max) { sum += first(); dequeue(); } else {…
Use the following node definition for this problem.struct NodeInt32{int32_t value; NodeInt32* next;} Write a function which searches a non-empty linked list for a target value. Its exact signature should be: NodeInt32* find(NodeInt32* head, int32_t target); The function should return the first node whose value equals target. If the target is not found in the list, then the function should return NULL.
#include<stdio.h> #include<stdlib.h> #include<conio.h> struct nodetype { struct nodetype *left ; int info ; struct nodetype *right; }; typedef struct nodetype *NODEPTR; NODEPTR maketree(int); NODEPTR getnode(void); void inordtrav(NODEPTR); int main(void) { NODEPTR root , p , q; printf("%s\n","Enter First number"); scanf("%d",&number); root=maketree(number); /* insert first root item */ while(scanf("%d",&number) !=EOF) { p=q=root; /* find insertion point */ while((number !=p->info) && q!=NULL) {p=q; if (number <p->info) q = p->left; else q = p->right; } q=maketree(number); /* insertion */ if (number==p->info) printf("%d is a duplicate \n",number); else if (number<p->info)…
An IntNode is a struct defined as: typedef struct IntNode struct { int dataVal; struct IntNode struct* nextNodePtr; } IntNode; Using this linked list diagram: Address of node: 2000 2800 1500 3600 3 65 34 76 head and this code snippet: IntNode * current; current = head; What is the value stored of current->nextNodePtr->nextNodePtr? 3 65 34 76 2000 2800 1500 3600 O O O O O O 0 0