Consider the following identity: n 2 2n Σ (1)² = (²7) k=0 (1) Perhaps it seems mysterious? But if you try a few small values of n, you may begin to suspect it is correct. (a) Suppose n€ N and that we have a set S of cardinality 2n containing n distinct objects, all coloured red, and n distinct objects, all coloured blue. Let k = Z satisfy 0 ≤ k

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Q: झाई उडका दु

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