Consider the following data for a dependent variable y and two independent variables, x; and xz; for these data SST = 15,194.4, and SSR 14,028.8.
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- Find the equation of the regression line for the following data set. x 1 2 3 y 0 3 4If the coefficient of determination between two independent variables is 0.33, what is the VIF? VIF= (Round to three decimal places as needed.)ONLY f, fi, fii3. Choose a country and research population data in order to fill out the table below INIDAa. Copy the population numbers counted each five years, as shown in the data base, for the years from 1950 to 2000. Add a column, t, measuring years since 1945. Year t population 1950 5 376,325,200 1955 5 409,880,595 1960 5 450,547,679 1965 5 499,123,324 1970 5 555,189,792 1975 5 623,102,897 1980 5 698,952,844 1985 5 784,360,008 1990 5 873,277,798 1995 5 963,922,588 2000 5 1,056,575,549 b. What is the country you selected? In what part of the world is it? What is the magnitude of its population numbers? (100,000’s, millions, hundred millions, billions?) Is it growing or shrinking in population size?c. Enter years since 1945 and your population numbers into your graphing calculator. Create a scatterplot of the data. Is the data growing or shrinking? Does it appear to be a linear pattern or non-linear? Explain your…
- The following information regarding a dependent variable (y) and an independent variable (x) is provided. x y 2 4 1 3 4 4 3 6 5 8 SSE = 6SST = 16Refer to Exhibit 14-4. The coefficient of determination is _____. a. .625 b. .7096 c. –.79062. Solve for the Pearson's r of the following data regarding height and weight of 10 students and interpret the results. Table for computation of other values is already arranged for you. Weight (x) Height (y) y? ху 38 135 38 Erty 38 44 141 147 51 145 32 132 51 149 77 164 32 130 Ex = Ey = Ex²= Ey2= Exy =The following equations were estimated using the data in LAWSCH85: Isalary = 9.90 – .0041 rank + .294 GPA (.24) (.0003) (.069) n = 142, R? = .8238 Isalary = 9.86 – .0038 rank + .295 GPA + .00017 age (.083) (.29) (.0004) (.00036) n = 99, R? = .8036 How can it be that the R-squared is smaller when the variable age is added to the equation?
- Please give Q2 for this dataIf your grade for your AMDM class is computed the following way: Homework – 10% Quizzes – 10% Tests – 60% Final Exam – 20% 1. What would your grade be if you had the following averages? • Test average = 84 • Final exam grade = 72 %3D • Homework = 90 • Quizzes = 95 %3DYou are given the following information: = 7.6491 Ax+1:9| = 6.59609 Ax+2:8| = 6.00768 i = 0.05 10Px = 0.83065 Calculate 2Px-
- The 98.6 degree standard for human body temperature was derived by a German doctor in 1868. In an attempt to verify his claim, Mackowiak, Wasserman, and Levine22 took temperatures from 148 healthy peopleover a 3-day period. A data set closely matching the one in Mackowiak’s article was derived by Allen Shoemaker, and appears in the Journal of Statistics Education.23 The body temperatures for these 130 individuals are shown in the relative frequency histogram that follows. See Attachment a. Describe the shape of the distribution of temperatures.b. Are there any unusual observations? Can you think of any explanation for these?c. Locate the 98.6-degree standard on the horizontal axis of the graph. Does it appear to be near the center of the distribution?Assume df = 13 and alpha = 0.05. If Pearson's r = 0.510, then the null _____ and the relationship between the variables is _____ . a. should be rejected; significant b. should be rejected; not significant c. should not be rejected; significant d. should not be rejected; not significantC6. Let's continue our analysis of offenders and victims of violent crime. In the following table, U.S. Department of Justice 2011 data for the sex of offenders and the sex of victims are reported. Sex of Offender Sex of Victim Male Female Male 3,760 450 Female 1,590 140 Source: U.S. Department of Justice, Expanded Homicide Data, Table 6, 2011.