Consider the following causal difference equation, which operates at a sample rate of 8 kHz: 5 3 y[n] − ² y[n − 1] + ²y[n − 2] = {x[n] - a) Find the system transfer function H(z)= Y(z) X(z) b) Plot the system's poles and zeros in the complex z-plane. Is the system stable? c) Determine the frequency response H(w) = H(z = ejw) for this system. d) Plot the magnitude and phase of the system's frequency response H(w). The frequency axis should be labeled in Hz. How would you characterize this system? e) Find a closed form expression for the system impulse response h[n]. Plot h[n] for n = 0:20.

Delmar's Standard Textbook Of Electricity
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Chapter21: Resistive-capacitive Series Circuits
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Please answer parts D and E. Thank you!!

Consider the following causal difference equation, which operates at a sample rate of 8 kHz:
3
1
y[n]y[n − 1] + y[n − 2] = x[n]
a) Find the system transfer function H(z)=
Y(z)
X(z)*
.
b) Plot the system's poles and zeros in the complex z-plane. Is the system stable?
c) Determine the frequency response H(w) = H(z = ejw) for this system.
d) Plot the magnitude and phase of the system's frequency response H(w). The frequency axis
should be labeled in Hz. How would you characterize this system?
e) Find a closed form expression for the system impulse response h[n]. Plot h[n] for n = 0:20.
Transcribed Image Text:Consider the following causal difference equation, which operates at a sample rate of 8 kHz: 3 1 y[n]y[n − 1] + y[n − 2] = x[n] a) Find the system transfer function H(z)= Y(z) X(z)* . b) Plot the system's poles and zeros in the complex z-plane. Is the system stable? c) Determine the frequency response H(w) = H(z = ejw) for this system. d) Plot the magnitude and phase of the system's frequency response H(w). The frequency axis should be labeled in Hz. How would you characterize this system? e) Find a closed form expression for the system impulse response h[n]. Plot h[n] for n = 0:20.
Final Answers
a) H(z) = 1/₂
1-5/4 = ² + 3 / 2²
b) zeros at
2=0,0 & pules at 2=
system is Stable
=) H (@w) = - 1/1/2
1- 5/4 ēju + 3/2 ēj 2 W //
w
8
3/4-1/2
Transcribed Image Text:Final Answers a) H(z) = 1/₂ 1-5/4 = ² + 3 / 2² b) zeros at 2=0,0 & pules at 2= system is Stable =) H (@w) = - 1/1/2 1- 5/4 ēju + 3/2 ēj 2 W // w 8 3/4-1/2
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