PROBLEM 4: LOGIC GATES Write out the Boolean functions the below simple circuits implement: A ?. A В
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- Basic Combinational Logic Circuits 2. Write the output expression for logic circuit: A B B XQ1/ Draw the logic circuit after simplify the circuit show below using K. map: A Y. C- Add filo B.(c) Figure Q3(c)(i) shows a register and Figure Q3(c)(ii) shows the input waveforms (CLOCK and Data in) to the circuit. A1 A9 A10 A2 Function generator A3 A11 A12 AS A13 A6 A14 A7 A15 Data in Bop.7) ip.r 82p.7) Logic analyser U1 U2 U3 U4 UO 6. 1. 6 1 6 INVERTER 3 CLK 3 CLK oCLK CLK 5 K K 5 K K 4027 Clock Function generator Figure Q3(c)(i) (i) Determine the type of register as shown in Figure Q3(c)(i).
- ii) For the circuit shown in Figure B9, a. Find logic functions for Y and Z. b. Simplify function Z using Boolean algebra. Y Figure B9 ABWhat logic function is performed by this circuit? VDD a. O d. e. A b. None OC AB AB A+B A+B O f. B AB M₁ M₂ M3 M4 F M54. For the logic circuit shown in Figure below write the required input condition (A,B,C) to make the output X =1. A B
- Q/What are the uses of logic gates?Design a combinational circuit with 3-inputs and 1-output. The output is equal to logic-1 when the binary value of the input is less than 3. And the output is logic-0 otherwise.4. Figure 2 shows a logic circuit with output F Figure 2. Logic circuit with gate I (AND), gate II (AND), gate III (NOT), gate IV (AND), gate V (EXOR) and gate VI (OR) a. Find the Boolean expression of output F. b. The simplified Boolean expression of Output F. c. If the input A and C were High and Input B was Low, what is output F:
- Task 6: Simplifying Boolean functions in EWB using the logic converter Simplify the following Boolean expression in EWB using the logic converter F (A, B, C) = AB'C'+ A'B'C'+ A'BC'+ A'B'CQ1. Design a 4-input, one output combinational logic circuit for the following input-output conditions: a) If the number of 1’s in inputs is more than or equal to 2 then the output is 1 ?. b) If the number of 1’s in inputs is less than 2 then the output is 0 ?.1. a. i. Draw the gates required to build a half adder are ii. When simplified with Boolean Algebra (x + y)(x + z) simplifies to : iii. The output of a logic gate is 1 when all its inputs are at logic 0, the gate is either :