Compute the following limit along lines of the form y = mx, for m 0, and along the parabola y = x. What canyou conclude?20xylim(x.y)→(0,0) x³ + yx.....Along the line y = mx, the limitlimf(x, y) =. Along the parabola y = x, the limit(x, y)→(0, 0)f(x, y) = |. Thereforef(x, у)(х, у) — (0, 0)limlim(х, у) — (0, 0)

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Compute the following limit along lines of the form y = mx, for m 0, and along the parabola y= x. What can you conclude? 20ху lim 3 (x,y)-(0,0) X° + yx ..... Along the line y = mx, the limit lim f(x, у) 3D |. Along the parabola y = x, the limit (х, у) — (0, 0) lim f(x, y) =. Therefore lim f(x, у) (X, y) (0, 0) (х, у) — (0, 0)

Compute the following limit along lines of the form y = mx, for m 0, and along the parabola y= x. What can you conclude? 20ху lim 3 (x,y)-(0,0) X° + yx ..... Along the line y = mx, the limit lim f(x, у) 3D |. Along the parabola y = x, the limit (х, у) — (0, 0) lim f(x, y) =. Therefore lim f(x, у) (X, y) (0, 0) (х, у) — (0, 0)

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter6: Applications Of The Derivative

Section6.CR: Chapter 6 Review

Problem 1CR

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