he continued with this solution to find I then did i=it' +it'' and got i(t)=6+5sin(3t) i didnt understand anything from what happened. please continue the solution where he left off and explain why he did what he did how he did it how i need to think in these type of questions and explain everything in extreme detail please Compute the current i(t) at the steady-state for Ao = 6, A, e(t) = 10 cos(3t), V,R = 10, 22, C = F and L = 1, Hi(t)Lme(t)R↑ Ao 6weiz21willhave two wsolvea circuiti(H = i(H)'iCH) |for w=0we haveSince Ao is constanti(+)H₂Foor w=2| w=0Deayzc+•RTNSociefor each omegai(+ //|w=3we have aa dc circuitAD=6AAc circuitW=3 /2=10AG=iCHIi(H²=6A3-ê21+2021= jw = 3;ze== -j

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Answered: Compute the current i(t) at the…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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he continued with this solution to find I then did i=it' +it'' and got i(t)=6+5sin(3t) i didnt understand anything from what happened. please continue the solution where he left off and explain why he did what he did how he did it how i need to think in these type of questions and explain everything in extreme detail please

Compute the current i(t) at the steady-state for Ao = 6, A, e(t) = 10 cos(3t), V,
R = 10, 22, C = F and L = 1, H
i(t)
L
m
e(t)
R
↑ Ao

6
we
iz
21
will
have two w
solve
a circuit
i(H = i(H)'
iCH) |
for w=0
we have
Since Ao is constant
i(+)
H₂
Foor w=2
| w=0
Deay
zc
+
•R
T
N
Socie
for each omega
i(+ //|w=3
we have a
a dc circuit
AD=6A
Ac circuit
W=3 /2=10
AG=iCHI
i(H²=6A
3-ê
21+20
21= jw = 3;
ze== -j

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