Compute QMn if fy = 60000 psi and fc = 4000 psi. Check the maximum permis to ensure ductile behavior. Design of Doubly Reinforced Beams For Problems 5.35 to 5.38, detemine the theoretical steel areas required for the sections shown. In cach case, the dimensions are limined to the values shown. If compression steel is required, assume it will be placed 3 in. from the compression face, f 4000 psi, and f, 60,000 psi. 5 25

Compute QMn if fy = 60000 psi and fc = 4000 psi. Check the maximum permis to ensure ductile behavior. Design of Doubly Reinforced Beams For Problems 5.35 to 5.38, detemine the theoretical steel areas required for the sections shown. In cach case, the dimensions are limined to the values shown. If compression steel is required, assume it will be placed 3 in. from the compression face, f 4000 psi, and f, 60,000 psi. 5 25

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter9: Composite Construction

Section: Chapter Questions

Problem 9.1.3P

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A beam cast monolithically has the following properties: bf=1200mm, t or hf = 110mm, bw=380mm and h=800mm. It is reinforced with 10D32mm grade 420MPa bars. Concrete strength is assumed to be 27.5MPa and the centroid of tension reinforcement is located 665mm from the outermost compression fiber. A. Determine maximum nominal moment to ensure tension controlled, kN-m. B. Calculate the balanced steel area, mm2. C. Calculate the balanced moment in kN-m.
A simply supported beam is reinforced with 5-25mm at the bottom And 2-20mm at the top if the beam. Concrete covering to centroid of reinforcement is 70mm at the top and 64 mm at the bottom. The beam has a gross depth of 450 mm and gross width of 300 mm. Fc’=28 mpa fy= 415 mpa. Assume bars are laid out in a single layer. calculate the following if the limiting tensile steel strain is 0.004 for ductile failure: a) depth if neutral axis from the extreme concrete compression fiber ( in mm, in whole number) b) design strength of the beam section ( in kn•m , in whole number) c) maximum service uniform live load over the entire span in Addition to a DL = 20 kn/m ( including weight of the beam) if it has a span of 6 m ( in kn, in whole number)
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The details of the cantilever beam are shown below. Use f’c = 28 MPa, fy = 415 MPa, and fyt = 275 MPa.Notes:• All dimensions are in millimeters.• Column reinforcement not shown for clarity• Column and beam are neither exposed to weather nor contact with the ground.• Analyze as singly reinforce beam only.• Neglect the weight of the beam.• Concrete is normal weight and reinforcements are galvanized. 1.what is the flexural capacity of the beam at face of support in kNm ? 2. What is the shear capacity of the beam at face of support in kN?3. What is the maximum Pu (kN) that can be applied at the free end of the beam considering flexure and shear?
A simply supported beam is reinforced with 5-p25 mm at the bottom and 2-020 mm at the top of the beam. Concrete covering to centroid of reinforcement is 70 mm at the top and 64 mm at the bottom of the beam. The beam has a gross depth of 450 mm and gross width of 300 mm. fc'= 28 MPa, fy = 415 MPa. Assume bars laid out in single layer. Calculate the following if the limiting tensile steel strain is 0.004 for a ductile failure: Depth of the neutral axis from the extreme concrete compression fiber to the nearest whole number = mm Design strength of the beam section to the nearest whole number = kN -m Maximum service uniform live load over the entire span in addition to a DL = 20 kN/m (including the weight of the beam) if it has a span of 6 m = kN/m (to the nearest whole number)
06. The composite bar, firmly attached to unyielding supports, is initially stress-free. What maximum axial load P can be applied if the allowable stresses are 10 ksi for aluminum and 18 ksi for steel? Steel Aluminum A = 1.25 in.? E = 10 x 106 psi A = 2.0 in.2 E = 29 x 106 psi SUMMARY OF ANSWERS P kips -15 in: -12 in.- CS Scanned with CamScanner
A simply supported beam is reinforced with 5-ϕ25 mm at the bottom and 2-ϕ20 mm at the top of the beam. Concrete covering to centroid of reinforcement is 70 mm at the top and 64 mm at the bottom of the beam. The beam has a gross depth of 450 mm and gross width of 300 mm. fc’= 28 MPa, fy = 415 MPa. Assume bars laid out in single layer. Calculate the following if the limiting tensile steel strain is 0.004 for a ductile failure: Depth of the neutral axis from the extreme concrete compression fiber to the nearest whole number = __ mm
A simply supported beam is reinforced with 5-ϕ25 mm at the bottom and 2-ϕ20 mm at the top of the beam. Concrete covering to centroid of reinforcement is 70 mm at the top and 64 mm at the bottom of the beam. The beam has a gross depth of 450 mm and gross width of 300 mm. fc’= 28 MPa, fy = 415 MPa. Assume bars laid out in single layer. Calculate the following if the limiting tensile steel strain is 0.004 for a ductile failure: Depth of the neutral axis from the extreme concrete compression fiber to the nearest whole number = mm Design strength of the beam section to the nearest whole number = kN·m Maximum service uniform live load over the entire span in addition to a DL = 20 kN/m (including the weight of the beam) if it has a span of 6 m = kN/m (to the nearest whole number)
A simply supported beam is reinforced with 5-ϕ25 mm at the bottom and 2-ϕ20 mm at the top of the beam. Concrete covering to centroid of reinforcement is 70 mm at the top and 64 mm at the bottom of the beam. The beam has a gross depth of 450 mm and gross width of 300 mm. fc’= 28 MPa, fy = 415 MPa. Assume bars laid out in single layer. Calculate the following if the limiting tensile steel strain is 0.004 for a ductile failure: Maximum service uniform live load over the entire span in addition to a DL = 20 kN/m (including the weight of the beam) if it has a span of 6 m = kN/m (to the nearest whole number)