Complete the table below using the attached circuit. Show solution Ipp 645.78MAVpp 64.578VVpp 20.353VIRMS 228.90mACurreil 68.774PAVres -VRMS 22.890VVAV 6.8774nVVL +VRMS 7.2143VVAV 2.0509nV500.00HZREF1REF1-REF2 -fv 500.00HZ!fvV500.00HZAL1V1100210mH24.0VrmsREF2500HZV0° 0 Zotal (ohms)ITotal (RMS)VR (RMS)VL (RMS)FreqXL(Hz)(ohms)RXmagangle|mag (V)anglemag (V)angle(ohms)(ohms)(mA)500

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Answered: Complete the table below using the…

Engineering

Electrical Engineering

Complete the table below using the attached circuit. Show solution

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.1MCQ: The rms value of v(t)=Vmaxcos(t+) is given by a. Vmax b. Vmax/2 c. 2Vmax d. 2Vmax

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

Complete the table below using the attached circuit. Show solution

Ipp 645.78MA
Vpp 64.578V
Vpp 20.353V
IRMS 228.90mA
Curreil 68.774PA
Vres -VRMS 22.890V
VAV 6.8774nV
VL +VRMS 7.2143V
VAV 2.0509nV
500.00HZ
REF1
REF1-
REF2 -
fv 500.00HZ!
fv
V
500.00HZ
A
L1
V1
1002
10mH
24.0Vrms
REF2
500HZ
V
0° 0

Zotal (ohms)
ITotal (RMS)
VR (RMS)
VL (RMS)
Freq
XL
(Hz)
(ohms)
R
X
mag
angle
|mag (V)
angle
mag (V)
angle
(ohms)
(ohms)
(mA)
500

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