Complete the spectroscopy data tables for a compound with molecular formula C5H13N. Determine the structure of the compound. Any labile protons, if they exist, will not be present in this particular 1H NMR spectrum. 8) Complete the spectroscopy data tables for a compound with molecular formula C5H13N.Determine the structure of the compound. Any labile protons, if they exist, will not bepresent in this particular 1H NMR spectrum.100D400030002000ISDO1000S00HAVENUMB ERI 11.90f1 (ppm)1.951.853.0 2.92.82.72.62.52.42.32.22.1 2.01.9 1.8 1.71.6 1.5 1.41.3 1.2 1.1 1.00.9130 120 110 100f1 (ppm)9080 7060 5040302010 0TRANSHITTANCEI%IFooz1.01.5.98- 8 Degrees of Unsaturation (show work):DOU = 0%3D[2 (5) +2-13+1-0]2.1°C NMR Data TableIR Data TableStretch (cm)BondBC Signal Chemical Shift (ppm) PC Signal> 3000 cmH-N44C-H sp3242ppam~3000 cm'26 ppm423'H NMR Data Table'H Signal Chemical Shift (ppm) IntegrationMultiplicitytoA2.75ppm2HProposed Structure1.90ppm1.54ppm2HCH30.95ppm6 HH, N-C-C-CH3CH3

Degree of unsaturation is 0 IR 3000 cm-1 due to Some C-H bond . 3300 cm-1 due to N-H bond . NMR…

Answered: Complete the spectroscopy data tables…

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter14: Mass Spectrometry

Section: Chapter Questions

Problem 14.27P: Following is the mass spectrum of an unknown compound. The two highest peaks are at m/z 120 and 122....

See similar textbooks

Related questions

Question

Complete the spectroscopy data tables for a compound with molecular formula C5H13N.
Determine the structure of the compound. Any labile protons, if they exist, will not be
present in this particular 1H NMR spectrum.

8) Complete the spectroscopy data tables for a compound with molecular formula C5H13N.
Determine the structure of the compound. Any labile protons, if they exist, will not be
present in this particular 1H NMR spectrum.
100
D
4000
3000
2000
ISDO
1000
S00
HAVENUMB ERI 1
1.90
f1 (ppm)
1.95
1.85
3.0 2.9
2.8
2.7
2.6
2.5
2.4
2.3
2.2
2.1 2.0
1.9 1.8 1.7
1.6 1.5 1.4
1.3 1.2 1.1 1.0
0.9
130 120 110 100
f1 (ppm)
90
80 70
60 50
40
30
20
10 0
TRANSHITTANCEI%I
Fooz
1.01.
5.98-

8 Degrees of Unsaturation (show work):
DOU = 0
%3D
[2 (5) +2-13+1-0]
2.
1°C NMR Data Table
IR Data Table
Stretch (cm)
Bond
BC Signal Chemical Shift (ppm) PC Signal
> 3000 cm
H-N
44
C-H sp3
2
42ppam
~3000 cm'
26 ppm
4
23
'H NMR Data Table
'H Signal Chemical Shift (ppm) Integration
Multiplicity
to
A
2.75ppm
2H
Proposed Structure
1.90ppm
1.54ppm
2H
CH3
0.95ppm
6 H
H, N-C-C-CH3
CH3

Expert Solution

Step 1

Degree of unsaturation is 0

3000 cm^-1due to Some C-H bond .

3300 cm^{-1 due to N-H bond .}

NMR

0.9 6 H doublet

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions