Complete the following Punnett squares that represent dihybrid crosses. P1 Cross: 2 Homozygous Dominant Traits x 2 Homozygous Recessive Traits = 100% 2 heterozygous traits AABB aabb AaBb F1 Cross: 2 Heterozygous Traits 2 Heterozygous Traits AaBb AaBb
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A: The genotypic cross-ratio along with the Punnett square is discussed in details in the step 2.
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- Here are the progeny of this cross: (Note that the categories are not in any particular order.)Fly type # of prog. Phenotype symbols Categorywt eyes black body wt wings 97 grn+ blk crv+Green eyes black body curved wings 709 ParentalGreen eyes wt body wt wings 9Green eyes black body wt wings 162wt eyes wt body wt wings 727wt eyes black body curved wings 12wt eyes wt body curved wings 179Green eyes wt body curved wings 105Total = 2000 9.) Write the phenotype symbols in the right-hand column. The first one has been done for you.10.) Next to that, label all fly categories as parental (NCOs), SCOs, and DCOs. One has been donefor you.11.) After each SCO/DCO label, write which gene got “unlinked” in these offspring.12.) Put these three genes into a genetic map in the proper order.13.) Calculate the genetic distance between the genes and label the map with these distances.14.) Calculate the cross-over interference15.) Return to questions #1-6 above. For question 6, you gave your opinion, but…Please consider the pedigree below. There are no cases of false paternity. I II III IV в 1 a. Which individual/s definitely has/have Bombay phenotype in the descendants of I-1 and I-2? b. What are the genotypes of individuals II-2 and III-2 at the AB0 and H loci? Please label your answers a and b, Il-2: and Ill-2:.In this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected || IV V 5600 orize 077808 15 10 9 10 CHO વ Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual does not display the disease phenotype. Carriers of the disease are not indicated. Information on disease status is not known for generation I and is omitted for the individuals represented by a symbol with an asterisk.…
- Please consider the pedigree below. There are no cases of false paternity. I B II A 2 3 III AB (A IV в 1 a. Which individual/s definitely has/have Bombay phenotype in the descendants of I-1 and I-2? b. What are the genotypes of individuals II-2 and III-2 at the ABO and H loci?I * 1 1 I 2 1 13 1 14 1 16r 1 11171 Using the pedigree you have constructed, complete the following Punnett square using A/a. 1) Show the cross between Baila and her non-albino husband if he had no Mother's Alleles albinism in his family history: Mother's genotype: Father's genotype: Genotype %: Phenotype %: o add speaker notes Father's AllelesI just want an explanation of what is in bold please. Lab Introduction: A dihybrid cross is a cross between individuals that involves two pairs of contrasting traits. To Predict the results of a dihybrid, cross all possible combinations of the four alleles from each parent must be considered. You will examine a dihybrid cross involving both color and texture. Purple (P), is dominate to yellow (p), and smooth texture (S) is dominant to wrinkled (s). Both parent plants are heterozygous for both traits. Review genetics and the use of Punnett squares in a biology text before doing this experiment.MATERIALS: Assume you have ear of Corn. You need a heterozygous X heterozygous 9:3:3:1, purple/yellow, starchy/sweet. PROCEDURE: From above please write out: The crop The parental (P) cross phenotype, genotype, gametes The F1 progeny Genotype and Phenotype Cross between two F1 Selfed testcross The F1 gametes The expected F2 results, genotype, phenotype, genotypic ratio, phenotypic ratio. 1.…
- Consider the selfed offspring of a AaBbCcDd individual: What is the probability that offspring will have the following genotypes: AABBCCDD AaBbCCDd ● • A_B_C_D_ BbCCDd ● ● ● ● ● 1/4 x 1/4 x 1/4 x 1/4= 1/256 1/2 x 1/2 x 1/4 x 1/2= 1/32 3/4 x 3/4 x 3/4 x 3/4= 81/256 1 x 1/2 x 1/4 x 1/2= 1/16 Same genotype as the parent? A.1 B. 1/1/12 C. D.1/8 E.1/16Purple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口 ロ口Pretending that Park shin-hye is heterozygous for A blood type marries Choi Tae-joon whose blood type is O. Show the possible blood types of their future children. 1. P1: 2. Punnett Square: 3. Genotype symbols: 4. Genotype in words: 5. Genotypic ratio: 6. Genotypic %: 7. Phenotype symbols: 8. Phenotype in words: 9. Phenotypic ratio: 10. Phenotypic %:
- The pedigree below shows the phenotypes of the ABO blood groups and Rhesus factors [positive (+) and negative (-)] for several members of a family. I (B+ AB- 1 2 3 4 II O- A+ В- B- AB+ A+ 1 2 4 5 6 a. What are the ABO blood group genotypes of individuals I-1 and I-2? b. Which child/ren of individual I-4 can donate blood to him? c. Which individual in the pedigree can donate blood to all the other individuals in the pedigree?A phenotypic ratio of 6:6:4 is possible between a male who is heterozygous free earlobes and heterozygous freckles, and a female who is homozygous free earlobes and heterozygous. The genotype of the female is written this way Eeff. Key: E = free earlobes e = attached earlobes F = freckles f = no freckles O If both statements are FALSE If both statements are TRUE O If the first statement is FALSE and the second statement is TRUE O If the first statement is TRUE and the second statement is FALSEA child has a blood type of “B positive”. This child is known to be a heterozygote at the ABO blood type gene and also a heterozygote at the Rh blood type gene. Select all of the choices below that show possible parents of this child. Question 7 options: Genotypes IA IA X IA IA Genotypes IA IA X IA i Genotypes IA i X IA i Genotypes IA IA X IA IB Genotypes IA IA X IB i Genotypes IA IA X i i Genotypes IA i X i i Genotypes IA i X IB i Genotypes IB IB X IB IB Genotypes IB IB X IB i Genotypes IB IB X IA i Genotypes IB IB X i i Genotypes IB i X IB i Genotypes IB i X i i Genotypes IB IB X IA IB Genotypes IA IA X IB IB Genotypes IA IB X IA IB Genotypes IA IB X IA i Genotypes IA IB X IB i Genotypes IA IB X i i Genotypes i i X i i Genotypes + + X + + Genotypes + + X + -…