Compare the cost to make 48 kg of ice using two different refrigerators; one has a COP of 5.00 and the other has a COP of 6.00. Electricity costs $0.10 per kWh. Using the same assumptions given in the example, find the cost difference (in dollars) between the refrigerators to freeze the water. Note: A kilowatt-hour [kWh] is a unit of energy. It is the amount of energy an appliance rated at 1 kW (1000 W) would consume if it ran for 1 hour. Therefore, 1 kWh = 3.60x106 J, as evident in the following unit conversion: 1 kWh x 1000W J/s 3600s X X h(hour) KW W = 3,600,000 J Hint: The cost difference will be a very small amount. Enter your answer using three significant figures. Hint cost difference = $
Compare the cost to make 48 kg of ice using two different refrigerators; one has a COP of 5.00 and the other has a COP of 6.00. Electricity costs $0.10 per kWh. Using the same assumptions given in the example, find the cost difference (in dollars) between the refrigerators to freeze the water. Note: A kilowatt-hour [kWh] is a unit of energy. It is the amount of energy an appliance rated at 1 kW (1000 W) would consume if it ran for 1 hour. Therefore, 1 kWh = 3.60x106 J, as evident in the following unit conversion: 1 kWh x 1000W J/s 3600s X X h(hour) KW W = 3,600,000 J Hint: The cost difference will be a very small amount. Enter your answer using three significant figures. Hint cost difference = $
Physics for Scientists and Engineers
10th Edition
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter21: Heat Engines, Entropy, And The Second Law Of Thermodynamics
Section: Chapter Questions
Problem 15P: An electric generating station is designed to have an electric output power of 1.40 MW using a...
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