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company surveyed 2300 men where 1104 of the men identified themselves as the primary grocery shopper in their household. Estimate the percentage of all males who identify themselves as the primary grocery shopper. Use a 98% confidence interval. Check the conditions first. A grocery store owner believed that only 46% of men are the primary grocery shopper for their family, and targets his advertising accordingly. He wishes conduct a hypothesis test to see if the fraction is in fact higher than 46%. What does your confidence interval indicate? Explain. What is the level of significance of this test? Explain. ) Check the conditions for constructing a confidence interval. Select all necessary conditions that have the appropriate explanation below. ☐ A. Randomization Condition: This condition is satisfied because there is nothing to indicate that the samples were not drawn randomly. ☐ B. 10% Condition: This condition is not satisfied because 2300 men are more than 10% of the population of men. ☐ C. Nearly Normal Condition: This condition is satisfied because there is nothing to indicate that the underlying population is not Normal. D. Success/Failure Condition: This condition is satisfied because there were more than 10 successes and failures. ☐ E. Nearly Normal Condition: This condition is not satisfied because it is highly unlikely that the population of men is Normal. ☐ F. Success/Failure Condition: This condition is not satisfied because there were fewer than either 10 successes or failures. G. 10% Condition: This condition is satisfied because 2300 men are less than 10% of the population of men. H. Randomization Condition: This condition is not satisfied because the samples were drawn from a convenience sample. Construct a 98% confidence interval for the sample proportion. The 98% confidence interval is (.). "Round to three decimal places as needed.)

company surveyed 2300 men where 1104 of the men identified themselves as the primary grocery shopper in their household. Estimate the percentage of all males who identify themselves as the primary grocery shopper. Use a 98% confidence interval. Check the conditions first. A grocery store owner believed that only 46% of men are the primary grocery shopper for their family, and targets his advertising accordingly. He wishes conduct a hypothesis test to see if the fraction is in fact higher than 46%. What does your confidence interval indicate? Explain. What is the level of significance of this test? Explain. ) Check the conditions for constructing a confidence interval. Select all necessary conditions that have the appropriate explanation below. ☐ A. Randomization Condition: This condition is satisfied because there is nothing to indicate that the samples were not drawn randomly. ☐ B. 10% Condition: This condition is not satisfied because 2300 men are more than 10% of the population of men. ☐ C. Nearly Normal Condition: This condition is satisfied because there is nothing to indicate that the underlying population is not Normal. D. Success/Failure Condition: This condition is satisfied because there were more than 10 successes and failures. ☐ E. Nearly Normal Condition: This condition is not satisfied because it is highly unlikely that the population of men is Normal. ☐ F. Success/Failure Condition: This condition is not satisfied because there were fewer than either 10 successes or failures. G. 10% Condition: This condition is satisfied because 2300 men are less than 10% of the population of men. H. Randomization Condition: This condition is not satisfied because the samples were drawn from a convenience sample. Construct a 98% confidence interval for the sample proportion. The 98% confidence interval is (.). "Round to three decimal places as needed.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
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company surveyed 2300 men where 1104 of the men identified themselves as the primary grocery shopper in their household. Estimate the percentage of all males who identify themselves as the primary grocery shopper. Use a 98% confidence interval. Check the conditions first. A grocery store owner believed that only 46% of men are the primary grocery shopper for their family, and targets his advertising accordingly. He wishes conduct a hypothesis test to see if the fraction is in fact higher than 46%. What does your confidence interval indicate? Explain. What is the level of significance of this test? Explain. ) Check the conditions for constructing a confidence interval. Select all necessary conditions that have the appropriate explanation below. ☐ A. Randomization Condition: This condition is satisfied because there is nothing to indicate that the samples were not drawn randomly. ☐ B. 10% Condition: This condition is not satisfied because 2300 men are more than 10% of the population of men. ☐ C. Nearly Normal Condition: This condition is satisfied because there is nothing to indicate that the underlying population is not Normal. D. Success/Failure Condition: This condition is satisfied because there were more than 10 successes and failures. ☐ E. Nearly Normal Condition: This condition is not satisfied because it is highly unlikely that the population of men is Normal. ☐ F. Success/Failure Condition: This condition is not satisfied because there were fewer than either 10 successes or failures. G. 10% Condition: This condition is satisfied because 2300 men are less than 10% of the population of men. H. Randomization Condition: This condition is not satisfied because the samples were drawn from a convenience sample. Construct a 98% confidence interval for the sample proportion. The 98% confidence interval is (.). "Round to three decimal places as needed.)
Transcribed Image Text:company surveyed 2300 men where 1104 of the men identified themselves as the primary grocery shopper in their household. Estimate the percentage of all males who identify themselves as the primary grocery shopper. Use a 98% confidence interval. Check the conditions first. A grocery store owner believed that only 46% of men are the primary grocery shopper for their family, and targets his advertising accordingly. He wishes conduct a hypothesis test to see if the fraction is in fact higher than 46%. What does your confidence interval indicate? Explain. What is the level of significance of this test? Explain. ) Check the conditions for constructing a confidence interval. Select all necessary conditions that have the appropriate explanation below. ☐ A. Randomization Condition: This condition is satisfied because there is nothing to indicate that the samples were not drawn randomly. ☐ B. 10% Condition: This condition is not satisfied because 2300 men are more than 10% of the population of men. ☐ C. Nearly Normal Condition: This condition is satisfied because there is nothing to indicate that the underlying population is not Normal. D. Success/Failure Condition: This condition is satisfied because there were more than 10 successes and failures. ☐ E. Nearly Normal Condition: This condition is not satisfied because it is highly unlikely that the population of men is Normal. ☐ F. Success/Failure Condition: This condition is not satisfied because there were fewer than either 10 successes or failures. G. 10% Condition: This condition is satisfied because 2300 men are less than 10% of the population of men. H. Randomization Condition: This condition is not satisfied because the samples were drawn from a convenience sample. Construct a 98% confidence interval for the sample proportion. The 98% confidence interval is (.). "Round to three decimal places as needed.)
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