Comment on each snippet with what the snippet does. Assume that there is an array, int arr [6] = {3, 1, 4, 1, 5, 9}, which starts at memory address 0xBFFFFF00. You may assume that each integer is stored in 4 bytes. Register a0 contains arr's address lw t0, 0(a0)lw t1, 8(a0)add t2, t0, t1 sw t2, 4(a0) 2.add t0, x0, x0 loop: slti t1, t0, 6 beq t1, x0, endslli t2, t0, 2 add t3, a0, t2 lw t4, 0(t3) sub t4, x0, t4 sw t4, 0(t3) addi t0, t0, 1 j loop end:pseudo-instructions are not allowed

The question asks for an explanation and analysis of two provided assembly code snippets that…

Comment on each snippet with what the snippet does. Assume that there is an array, int arr [6] = {3, 1, 4, 1, 5, 9}, which starts at memory address 0xBFFFFF00. You may assume that each integer is stored in 4 bytes. Register a0 contains arr's address

Comment on each snippet with what the snippet does. Assume that there is an array, int arr [6] = {3, 1, 4, 1, 5, 9}, which starts at memory address 0xBFFFFF00. You may assume that each integer is stored in 4 bytes. Register a0 contains arr's address

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter3: Data Representation

Section: Chapter Questions

Problem 12VE

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Concept explainers

Hash Table

A hash table also called a hash map, is a data structure that maps key-value pairs. The hash table can be used in complex systems to provide fast access and compact storage. A hash table is a structure that stores data in an abstract data type kind of associative array. It keeps data in an array format, with a distinct index value for every data value. If the index of the required data is known, then the data can be accessed very easily.

Question

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Comment on each snippet with what the snippet does. Assume that there is an array, int arr [6] = {3, 1, 4, 1, 5, 9}, which starts at memory address 0xBFFFFF00. You may assume that each integer is stored in 4 bytes. Register a0 contains arr's address

lw t0, 0(a0)

lw t1, 8(a0)

add t2, t0, t1

sw t2, 4(a0)

add t0, x0, x0

loop: slti t1, t0, 6

beq t1, x0, end

slli t2, t0, 2

add t3, a0, t2

lw t4, 0(t3)

sub t4, x0, t4

sw t4, 0(t3)

addi t0, t0, 1

j loop

end:

pseudo-instructions are not allowed

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