Cinnabar eye color is a sex-linked, recessive characteristic in fruit flies. If a female having cinnabar eyes is crossed with a wild-type male, what percentage of the F1 males will have cinnabar eyes?
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- Cinnabar eye color is a sex-linked, recessive characteristic in fruit flies. If a female having cinnabar eyes is crossed with a wild-type male, what percentage of the F1 males will have cinnabar eyes?
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- Cinnabar eyes is a sex-linked, recessive characteristic in fruit flies. If a female having cinnabar eyes is crossed with a wild-type male, what percentage of the F1 males will have cinnabar eyes?In a species of bird, feather colour is determined by a single, non-autosomal gene that shows complete penetration. A red-feathered female mates with a blue-feathered male, and all the F1 males are blue-feathered and the F1 females are red-feathered. When the F1 individuals are crossed, all the F2 males are again blue-feathered and the F1 females are again red- feathered. Provide the genotype of the F2 males and females. Clearly indicate which genotype is associated with males and females, respectively. Binomial Expansion 1 a+b 2 a' + 2ab + b? 3 a'+ 3a'b + 3ab + b a + 4a'b + 6a'b + 4ab + b 5 a + Sa*b + 10a'b2 + 100'b + Sab + bIn fruit flies, the following X-linked traits are found: white eyes are recessive to red eyes, ebony body is recessive to gray body, and short wings is recessive to long wings. A cross was made between wild-type males with red eyes, long wings, and gray bodies and females with white eyes, short wings, and ebony bodies. Female heterozygote resulting from this cross, which had red eyes, long wings, and gray bodies, were then crossed with males with white eyes, short wings, and ebony bodies. The F2 generation data is obtained below: 1299 white eyes, short wings, ebony bodies 1367 red eyes, long wings, gray bodies 99 white eyes, short wings, gray body 89 red eyes, long wings, ebony bodies 49 white eyes, long wings, ebony bodies 49 red eyes, short wings, gray bodies 1 red eyes, short wings, ebony bodies 1 white eyes, long wings, gray bodies A) Calculate the map distance separating the three genes B) Which gene is in the middle?
- The following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyWhat information do you know based on the question and your…The following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyAnalyze data. Make a drawing. Make a calculation.The following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyWhat topic in genetics does this question address?
- The following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyA. Calculate the map distances separating the three genes.B. Is…PURPLE VESTIGIAL DIHYBRID CROSS In the parental generation, you mate a pure-breeding wild-type female (put/pu+;vg+/vg+) with a pure-breeding purple, vestigial (pu/pu;vg/vg) to produce an F1 generation that is all wild-type (pu*/pu;vg+/vg). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (pu*/pu;vg+/vg) with tester males, which are purple, vestigial (pu/pu;vg/vg). The offspring of this dihybrid testcross are: Phenotype Genotype Tester Gamete Dihybrid Gamete Number Wild-type 437 417 77 59 Purple, vestigial Vestigial Purple Copy the table into your notes and derive the dihybrid gametes following the example in the first section. The columns in blue (phenotypes and numbers of offspring) are what you can see and count. The genotypes of the testcross offspring (orange) must be deduced from the phenotypes and knowing that the tester contributed pu vg gametes. Finally, you can deduce the dihybrid gametes (green) by subtracting the tester gamete contribution…You are studying the inheritance pattern of hair color in troll dolls, which have XY sex determination. You cross a true-breeding blue-haired male with a true-breeding orange-haired female. The F1 offspring (males and females) are all orange-haired. You cross an F1 orange-haired female to an F1 orange-haired male. What phenotypic ratio would you expect if the troll doll hair gene is X-linked? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "O" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use 2:1 rather than 4:2). orange-haired females : blue-haired females : orange-haired male : blue haired males What phenotypic ratio would you expect if the troll doll hair gene is autosomal? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "0" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use 2:1 rather than 4:2).…
- You are studying the inheritance pattern of hair color in troll dolls, which have XY sex determination. You cross a true-breeding blue-haired male with a true-breeding orange- haired female. The F1 offspring (males and females) are all orange-haired. You cross an F1 orange-haired female to an F1 orange-haired male. What phenotypic ratio would you expect if the troll doll hair gene is X-linked? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "0" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use,2:1 rather than 4:2). 1:1 € 1:1 1:1 orange-haired females : 1:1 orange-haired male : What phenotypic ratio would you expect if the troll doll hair gene is autosomal? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "0" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use 2:1 rather than 4:2). 1:1 blue-haired females :…In fruit flies, L= long wings and l = short wings. When a long-winged fly is crossed with a short winged fly, the offspring exhibit a 1:1 ratio. What is the genotype of the parental flies?In fruit flies, Cinnabar eyes are encoded by a recessive allele located on the X chromosome. If a female having cinnabar eyes is crossed with a wild-type male, what is the phenotypic ratio among male offspring?