(Chapter 4 b) Given the following information:JobArrival TimeCPU CycleA15В22314D610E9.1Compute the average turnaround time using SJN scheduling algorithm.а. 18.8b. 19.8c. 20.8d.21.8 QUESTION 11Using the same information given on question (chapter 4 b), compute the average waiting time usingFCFS scheduling algorithm.a. 24.4O b. 17.8O. 16.8O d. 18.6

Name: (Chapter 4 b) Given the following information:JobArrival TimeCPU Cycl
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Description: (Chapter 4 b) Given the following information:JobArrival TimeCPU CycleA15В22314D610E9.1Compute the average turnaround time using SJN scheduling algorithm.а. 18.8b. 19.8c. 20.8d.21.8 QUESTION 11Using the same information given on question (chapter 4

For the SJF algorithm the shortest job is done first but for no premtive when cpu is assigned to any…

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(Chapter 4 b) Given the following information: Job Arrival Time CPU Cycle A 15 B 2 C 3 14 D 10 E 9. 1 Compute the average turnaround time using SJN scheduling algorithm. O a. 18.8 b. 19.8 O. 20.8 O d.21.8

(Chapter 4 b) Given the following information: Job Arrival Time CPU Cycle A 15 B 2 C 3 14 D 10 E 9. 1 Compute the average turnaround time using SJN scheduling algorithm. O a. 18.8 b. 19.8 O. 20.8 O d.21.8

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Transcribed Image Text (Micro processer 8086) Q1) Choose the correct answer: 1. One of the following instructions is correct: a. MUL 67 b. LEA BL.[SI] (2. AS) c. LALF d. Neither a,b nor c 2. Suppose we have SS starts at B4102 H, CS ends at E4250H. The suitable point for DS to start so there are no overlapping of the segments is: c. C4200 H d. C4300 H a. C4000 H b. C4100 H 3. If you have AX-0208H, BL=D8H, the results of performing IDIV BL in AX is: a. 00F3 H b. F300 H c. 5802 H d. 0258 H 4. The Execution Unit includes: a. Instruction pointer b. Status register c. Address generation d. Neither a,b nor c 5. The compare instruction and test instruction are similar in : a. Both instructions are subtraction methods b. Both instructions effect on ZF, SF & PF. c. Both instructions store the result in the destination operand d. Neithe a,b nor c 6. The data bus in 8088 Mp is: a. 16-bit unidirectional lines c. 8-bit unidirectional lines b. 16-bit bidirectional lines d. 8-bit bidirectional…
نقطة واحدة (h If the CPU scheduling policy is priority scheduling with pre-emption, the ATAT will be 16 ms O 15 ms O 16.2 ms O 16.4 ms O 15.8 ms O none of these O
Refer to the code below determine whether this code is correct, and if not, correct any mistakes. Find the speedups and efficiencies of the parallel odd-even transposition. Does the program obtain linear speedups? Is it scalable? Is it strongly scalable? Is it weakly scalable? After correcting the mistakes, execute the code in CUDA or OpenMP and measure any performance improvement in terms of speedups and scalability. Process Pi evenprocess =(i%2 ==2); evenphase = 1; for(step =0; step < n; step++,evenphase = !evenphase) { if((evenphase && evenprocess) || (!evenphase && !evenprocess) { send (&a, Pi+1); recv (&x, Pi+1); if (x<a) a =x; } else { recv (&x, Pi-1); send (&a, Pi-1); if (x > a) a = x; } }
Given rax = 0x0000000200000100, rbx = 0x0000000000000100, and rcx = 0x0000000000000001,and the following values in memoryaddress -> byte at that address0x0000000000000100 -> 0x010x0000000000000101 -> 0x000x0000000000000102 -> 0x000x0000000000000103 -> 0x000x0000000000000104 -> 0x020x0000000000000105 -> 0x000x0000000000000106 -> 0x000x0000000000000107 -> 0x00what is the new value in %rax after the following operation?subq -0x04(%rbx, %rcx, 4), %rax
Suppose a program segment consists of a purely sequential part which takes 100 cycles to execute, and an iterated loop which takes 400 cycles per iteration. Assume that the loop is dependent on the sequential part, i.e., both parts cannot run in parallel. Also assume that the loop iterations are independent, and cannot be further parallelized. If the loop is to be executed 100 times, what is the maximum speedup possible using an infinite number of processors (as many processors as you could possibly need) compared to a single processor?
Please let me know if these are true or false! In multiprocessors with a shared physical main memory, an access to a word of main memory always takes about the same amount of time no matter which word is being accessed and by which processor: T/F? When reading data from a magnetic disk, the rotational latency increases linearly with the size of the request: T/F? SSD is faster to access than magnetic disk, but slower than DRAM main memory: T/F? The primary purpose of RAID is for data backups: T/F? Typically, data parallelism offers greater opportunities for achieving highly-parallel execution than does functional parallelism: T/F? In MIPS systems, one way to implement locks is with the MIPS test-and-set machine language instruction: T/F?
Consider the following set of processes, with the length of the CPU burst time given in milliseconds: Process Burst Time (ms) Priority Arrival Time (ms) P1 12 5 P2 6 P3 4 2 2 Р4 15 4 P5 2 10
aton 24 Following is a mapping of Logical Memory to Physical Memory using a Page Table. You are required to fill the Page Table: yet vered Physienl Memery ced out of Logical Mumery Рage 0 Page 1 1 Page 5 2 Page 2 3 Page 4 ag question Рage 2 Page 3 Page 4 5 Page 0 6. 7 Page 1 8 Page 3 Page 5 Page Table
M E su meleing... Problem 4 This problem is very similar to Problem 2. and you should use your solution to Problem 2 as starter code. The inputs are the same, but the output is a bit different: rather than telling the user how many slices in total will be left over, display the number of whole tiramisus plus number of slices from the tiramisu that had some slices removed. Sample Runs: nickemimi MINGW64 /c/Nick/CSULA/Cs2011/Code S java TiramisUAndPeoplez How many tiramisus? 5 How many slices per tiranisu? 4 How many people? 8 If you split ail tiranisus evenly among 8 people, you will have 1 full melting... nickamimi MINGW64 /c/Nick/CSULA/Cs2011/Code S java TiramisUandPeople2 HOW many tiramisus? 3 How many slices per tiramisu? 4 HOw many people? 7 If you split all tiramisus evenly among 7 people, you wi11 have 1 full ft over. melting... nickamini MINGW64 /c/Nick/CSULA/CS2011/Code S java TiramisUAndreoplez How many tiranisus? S HOW many slices per tiramisu? 5 HOW many people? 9 If you…
8086Mp memory is logically divided into segments, the size of each segment is: 1Mbyte 64Kbyte 128Kbyte 2Kbyte 10Kbyte 32Кbyte 1Kbyte Let CS=5A71H, IP=BF6CH. What is the name of the memory segment given in the following figure AFTER executing the instruction (CALL [BX+DI] )? if IPnew=8C23H. * BF H 6F80BH 6C H 6F80AH Extra segment Stack segment Code segment Data segment
Solve the 8085 Write a program to load twenty memory locations starting from 8005H, where each location's content should increases by 2 over the previous one, however, the first location should contain 04H, assuming that the programs start at memory location 9009H?
Q1/ Two word - wide unsigned integers are stored at the physical memory addresses 0400H and 0402H respectively. Write an instruction sequence that computes and stores their sum, difference, product, and quotient. Store these results at consecutive memory locations starting at physical address 0410H in memory. To obtain the difference, subtract the integer at 0402H from the integer at 0400H. For the division, divide the integer at 0400H by the integer at 0402H. Use the register indirect relative addressing mode to store the various result.