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Ca(OH)2 (aq) + H₂SO4 (aq) →+ 2 H₂O (1) + CaSO4 (aq) (This is LIMITING REACTANT: H.SO, is the Limiting Reactant) Reaction Type: Neutralization Grams of Product (List the Product and the Amount): 0.180 g H₂O and 0.681 g CaSO4 ? g H₂0 = 1.839 g Ca(OH)2 x 1 mol Ca(OH)2 x 74.10 g Ca(OH)2 ? g H₂O 25.0 mL H₂SO4 x = Ca (OH)₂ amount = 1.839 g GIVEN 1.469 g ONLY USE THE Limiting Reactant TO DETERMINE THE AMOUNT OF THE REMAINING PRODUCT(S). ? g H₂O = 25.0 mL H₂SO4 x IL H₂SO4 x 0.200 mol H₂SO4 x 1 mol CaSO4 x 136.14 g CaSO4 1000 mL H₂SO4 1L H₂SO4 1 mol H₂SO4 1 mol CaSO4 ? g Ca (OH)₂ USED = 25.0 mLH₂ SO4 X- = 0.3705 g Ca (OH)₂ Amount of Ca(OH)2 remaining in the container = -- 1L H₂SO4 x 0.200 mol H₂SO4 x 2 mol H₂O x 18.02 g H₂O = 0.180 g H₂0 1000 mL H₂SO4 1L H₂SO4 1 mol H₂SO4 1 mol H₂O 2 mol H₂O x 18.02 g H₂O = 1 mol Ca(OH)2 1 mol H₂O 1 LH₂ SO4 1000 mL H₂ SOA X LEFT 0.8944 g H₂O given - Ca (OH)2 amount used 0.3705 g USED OVER = EXCESS 0.200 mol H₂ SO4 1 mol Ca (OH)2 1 LH₂ SOA 1 mol H₂ SO₂ X X 0.681 g CaSO4 74.093 g 1 mol Ca (OH)₂ 1 mol Ca (OH)₂

Ca(OH)2 (aq) + H₂SO4 (aq) →+ 2 H₂O (1) + CaSO4 (aq) (This is LIMITING REACTANT: H.SO, is the Limiting Reactant) Reaction Type: Neutralization Grams of Product (List the Product and the Amount): 0.180 g H₂O and 0.681 g CaSO4 ? g H₂0 = 1.839 g Ca(OH)2 x 1 mol Ca(OH)2 x 74.10 g Ca(OH)2 ? g H₂O 25.0 mL H₂SO4 x = Ca (OH)₂ amount = 1.839 g GIVEN 1.469 g ONLY USE THE Limiting Reactant TO DETERMINE THE AMOUNT OF THE REMAINING PRODUCT(S). ? g H₂O = 25.0 mL H₂SO4 x IL H₂SO4 x 0.200 mol H₂SO4 x 1 mol CaSO4 x 136.14 g CaSO4 1000 mL H₂SO4 1L H₂SO4 1 mol H₂SO4 1 mol CaSO4 ? g Ca (OH)₂ USED = 25.0 mLH₂ SO4 X- = 0.3705 g Ca (OH)₂ Amount of Ca(OH)2 remaining in the container = -- 1L H₂SO4 x 0.200 mol H₂SO4 x 2 mol H₂O x 18.02 g H₂O = 0.180 g H₂0 1000 mL H₂SO4 1L H₂SO4 1 mol H₂SO4 1 mol H₂O 2 mol H₂O x 18.02 g H₂O = 1 mol Ca(OH)2 1 mol H₂O 1 LH₂ SO4 1000 mL H₂ SOA X LEFT 0.8944 g H₂O given - Ca (OH)2 amount used 0.3705 g USED OVER = EXCESS 0.200 mol H₂ SO4 1 mol Ca (OH)2 1 LH₂ SOA 1 mol H₂ SO₂ X X 0.681 g CaSO4 74.093 g 1 mol Ca (OH)₂ 1 mol Ca (OH)₂

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 94QRT
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Ca(OH)2 (aq) + H₂SO4 (aq) →+ 2 H₂O (1) + CaSO4 (aq) (This is LIMITING REACTANT: H.SO, is the Limiting Reactant) Reaction Type: Neutralization Grams of Product (List the Product and the Amount): 0.180 g H₂O and 0.681 g CaSO4 ? g H₂0 = 1.839 g Ca(OH)2 x 1 mol Ca(OH)2 x 74.10 g Ca(OH)2 ? g H₂O 25.0 mL H₂SO4 x 1L H₂SO4 x 0.200 mol H₂SO4 x 2 mol H₂O x 18.02 g H₂O = 0.180 g H₂0 1000 mL H₂SO4 1L H₂SO4 1 mol H₂SO4 1 mol H₂O ONLY USE THE Limiting Reactant TO DETERMINE THE AMOUNT OF THE REMAINING PRODUCT(S). ? g H₂O = 25.0 mL H₂SO4 x IL H₂SO4 x 0.200 mol H₂SO4 x 1 mol CaSO4 x 136.14 g CaSO4 1000 mL H₂SO4 1L H₂SO4 1 mol H₂SO4 1 mol CaSO4 ? g Ca (OH)₂ USED = 25.0 mLH₂ SO4 X- = 0.3705 g Ca (OH)2 Amount of Ca(OH)2 remaining in the container = Ca (OH)₂ amount = 1.839 g GIVEN = 1.469 g -- IL H₂ SO4 1000 mL H₂ SO4 2 mol H₂O x 18.02 g H₂O = 1 mol Ca(OH)2 1 mol H₂O X LEFT 0.8944 g H₂O given - Ca (OH)2 amount used 0.3705 g USED OVER = EXCESS 0.200 mol H₂ SO4 1 mol Ca (OH)2 1 LH₂ SO₁ 1 mol H₂ SO4 X X 0.681 g CaSO4 74.093 g 1 mol Ca (OH)₂ 1 mol Ca (OH)₂
Transcribed Image Text:Ca(OH)2 (aq) + H₂SO4 (aq) →+ 2 H₂O (1) + CaSO4 (aq) (This is LIMITING REACTANT: H.SO, is the Limiting Reactant) Reaction Type: Neutralization Grams of Product (List the Product and the Amount): 0.180 g H₂O and 0.681 g CaSO4 ? g H₂0 = 1.839 g Ca(OH)2 x 1 mol Ca(OH)2 x 74.10 g Ca(OH)2 ? g H₂O 25.0 mL H₂SO4 x 1L H₂SO4 x 0.200 mol H₂SO4 x 2 mol H₂O x 18.02 g H₂O = 0.180 g H₂0 1000 mL H₂SO4 1L H₂SO4 1 mol H₂SO4 1 mol H₂O ONLY USE THE Limiting Reactant TO DETERMINE THE AMOUNT OF THE REMAINING PRODUCT(S). ? g H₂O = 25.0 mL H₂SO4 x IL H₂SO4 x 0.200 mol H₂SO4 x 1 mol CaSO4 x 136.14 g CaSO4 1000 mL H₂SO4 1L H₂SO4 1 mol H₂SO4 1 mol CaSO4 ? g Ca (OH)₂ USED = 25.0 mLH₂ SO4 X- = 0.3705 g Ca (OH)2 Amount of Ca(OH)2 remaining in the container = Ca (OH)₂ amount = 1.839 g GIVEN = 1.469 g -- IL H₂ SO4 1000 mL H₂ SO4 2 mol H₂O x 18.02 g H₂O = 1 mol Ca(OH)2 1 mol H₂O X LEFT 0.8944 g H₂O given - Ca (OH)2 amount used 0.3705 g USED OVER = EXCESS 0.200 mol H₂ SO4 1 mol Ca (OH)2 1 LH₂ SO₁ 1 mol H₂ SO4 X X 0.681 g CaSO4 74.093 g 1 mol Ca (OH)₂ 1 mol Ca (OH)₂
Balanced Chemical Equation Reaction Type: At completion of reactions: Grams of calcium hydroxide Grams of sulfuric acid Grams of water Grams of calcium sulfate
Transcribed Image Text:Balanced Chemical Equation Reaction Type: At completion of reactions: Grams of calcium hydroxide Grams of sulfuric acid Grams of water Grams of calcium sulfate
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