Calculate the Virtual Condition of the PIN in the drawing below:1.000O 1.000.504.982C1.0082.000Ø.995-1.000+0.008MABC6.00O None of these answers is correctX3.00001.005-1.030+0.005MABCBA.XX = .01ANGLES= ± 1°

Answered: Calculate the Virtual Condition of the…

Calculate the Virtual Condition of the PIN in the drawing below: 1.000 C 2.000 Ø.995-1.000 +0.008MABC 6.00 X 3.000 01.005-1.030 +0.005MABC B A

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Free Body Diagram

The system of forces acting on a body tends to either rotate it or make the body undergo motion. In general, when an external agent exerts a force on a body, the body undergoes translational motion and rotational motion. The body has six degrees of freedom under the influence of that force. Here, three degrees of freedom are from the translational motion while the other three are from the rotation motion. However, sometimes the bodies are not allowed to undergo any motion and are fixed, under such conditions the body is said to be constrained.

Question

Calculate the Virtual Condition of the PIN in the drawing below:
1.000
O 1.000
.504
.982
C
1.008
2.000
Ø.995-1.000
+0.008MABC
6.00
O None of these answers is correct
X
3.000
01.005-1.030
+0.005MABC
B
A
.XX = .01
ANGLES= ± 1°

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Calculate the Resultant Condition of the HOLE in the drawing below: 1.000 O 1.060 O 1.000 O.530 .982 C 2.000 Ø.995-1.000 +0.008MABC 6.00 O None of these answers is correct X 3.000 Y 01.005-1.030 +0.005MABC B A XX = .01 ANGLES = ± 1°
Calculate the Maximum Y distance on the drawing below: 1.000 O .510 O .500 2.009 C O .460 2.000 Ø.995-1.000 6.00 O None of these answers is correct 0.008 MABC X 3.000 01.005-1.030 +0.005MABC B A .XX = .01 ANGLES ± 1°
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Calculate the Minimum Y distance on the drawing below: 1.000 O .500 1.966 O .460 O 2.000 O .510 C 2.000 Ø.995-1.000 6.00 0.008MABC X 3.000 01.005-1.030 +0.005MABC B A .XX = .01 ANGLES ± 1°
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Show full and complete solution Change x in 7x to 78
2. Nominal size is 40mm, the clearance is between 24µm and 92µm, the span of the clearance fit is not bigger than 68µm. To find out: O the upper/lower limit deviation of the hole; the upper/lower limit deviation of the shaft; ® the minimum clearance and the maximum clearance; Designation of fit; Illustration of tolerance interval/zone. The answer is as follows:
B C A D Using the above drawing, apply an H7/g6 Sliding clearance fit to the Ø20 hole and shaft. Apply a U7/h6 Force fit to the Ø10 hole and shaft. Fill in the metric tolerances in the boxes provided below using the preferred method shown in the following example: Example: Ø 20.240 20.110 (Ø20 C11) A (이 (이 (이 (이 Q Q B.
already answered in bartleby. please do not copy! STATICS OF RIGID BODIES (UPVOTE WILL BE GIVEN. PLEASE WRITE THE COMPLETE SOLUTIONS AND FBD LEGIBLY. NO LONG EXPLANATION NEEDED. ANSWER IN 3 DECIMAL PLACES. BOX THE FINAL ANSWERS.) Let a = 11.66 mm