Calculate the value of the rate constant for each run and calculate the average value. Indicate the units for the rate costant. Given :  Rate of reaction for run 1= 1.08 x10-6 M/s Rate law for Run 1 : 1.08 x10-6 M/s = k[0.00125 M]x[0.0088 M]y                                        Eqn 1 Rate of reaction for run 2= 1.58 x10-6 M/s Rate law for Run 2 : 1.58 x10-6 M/s = k[0.0025 M]x[0.0088 M]y                     Eqn 2 Rate of reaction for run 3 = 1.99 x10-6 M/s Rate law for Run 3 : 1.99 x10-6 M/s = k[0.00125 M]x[0.0176 M]y                             Eqn 3

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Calculate the value of the rate constant for each run and calculate the average value. Indicate the units for the rate costant. Given : 

Rate of reaction for run 1= 1.08 x10-6 M/s

Rate law for Run 1 : 1.08 x10-6 M/s = k[0.00125 M]x[0.0088 M]y                                        Eqn 1

Rate of reaction for run 2= 1.58 x10-6 M/s

Rate law for Run 2 : 1.58 x10-6 M/s = k[0.0025 M]x[0.0088 M]y                     Eqn 2

Rate of reaction for run 3 = 1.99 x10-6 M/s

Rate law for Run 3 : 1.99 x10-6 M/s = k[0.00125 M]x[0.0176 M]y                             Eqn 3

 

兴 兴
Mass of potassium iodide used
O.alg
Mass of sodium thiosulfate pentahydrate used
20.1159
Volume of 30% hydrogen peroxide
-2ml
6.0025x 2so
Part A.Rate law
33
3 =
vi/20 x30
LUTED
0.00A Sx250:
1000
Temperature
vi=(3.20/30- - 2mu
Run #1
Run #2
Run #3
Time until permanent blue color appears
||门
1.060-158*
- 99 x10
Mis
Rate of reaction
Rate law
Rate constant
Femperature of solution
0.025
-0.0a5 mo
mol Icx (son Cx/100mL
l)LX0.05OL
1.X0.050L
proj
=0.00128 mol
000125mol x lbb0gmol
al9
22 - 5
Transcribed Image Text:兴 兴 Mass of potassium iodide used O.alg Mass of sodium thiosulfate pentahydrate used 20.1159 Volume of 30% hydrogen peroxide -2ml 6.0025x 2so Part A.Rate law 33 3 = vi/20 x30 LUTED 0.00A Sx250: 1000 Temperature vi=(3.20/30- - 2mu Run #1 Run #2 Run #3 Time until permanent blue color appears ||门 1.060-158* - 99 x10 Mis Rate of reaction Rate law Rate constant Femperature of solution 0.025 -0.0a5 mo mol Icx (son Cx/100mL l)LX0.05OL 1.X0.050L proj =0.00128 mol 000125mol x lbb0gmol al9 22 - 5
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