Calculate the standard enthalpy for the reaction: 4NH3(g) + 502(g) - 4NO(g) + 6H20(g), given the following data: N2(g) + O2(g) - 2NO(g) AHxn = -43.1 kcal mol N2(g) + 3H2(g) - 2NH3(g) AHrxn = -21.9 kcal mol" %3D 2H2(g) + O2(g) - 2H20(g) AH pxn = -115.6 kcal mol1 Round your answer to 2 decimal places.

Chemistry: The Molecular Science
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ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
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Calculate the standard enthalpy for the reaction: 4NH3(g) + 502(g) - 4NO(g) + 6H2O(g), given the following data:
N2(g) + O2(g) - 2NO(g)
AH,xn = -43.1 kcal mol
%3D
N2(g) + 3H2(g) - 2NH3(g)
AHxn = -21.9 kcal mol
2H2(g) + O2(g) - 2H,0(g)
AHxn = -115.6 kcal mol1
Round your answer to 2 decimal places.
Transcribed Image Text:Calculate the standard enthalpy for the reaction: 4NH3(g) + 502(g) - 4NO(g) + 6H2O(g), given the following data: N2(g) + O2(g) - 2NO(g) AH,xn = -43.1 kcal mol %3D N2(g) + 3H2(g) - 2NH3(g) AHxn = -21.9 kcal mol 2H2(g) + O2(g) - 2H,0(g) AHxn = -115.6 kcal mol1 Round your answer to 2 decimal places.
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