Calculate the number of formula units of calcium phosphate produced when 19.50 grams of calcium fluoride reacts with excess iron (II) phosphate. Iron (II) fluoride is produced as well. Recall that formula units are equivalent to molecules as a unit.

Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter5: Stoichiometry
Section: Chapter Questions
Problem 118E: Consider the following unbalanced equation: Ca3(PO4)2(s)+H2SO4(aq)CaSO4(s)+H3PO4(aq) What masses of...
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In 6-10 sentences list steps and considerations used to solve the problem.

 

Calculate the number of formula units of calcium phosphate produced when 19.50 grams of
calcium fluoride reacts with excess iron (II) phosphate. Iron (II) fluoride is produced as well. Recall
that formula units are equivalent to molecules as a unit.
Al Hypothesis: State your strategy for how to solve the problem in 2-4 sentences. Note that this should
Transcribed Image Text:Calculate the number of formula units of calcium phosphate produced when 19.50 grams of calcium fluoride reacts with excess iron (II) phosphate. Iron (II) fluoride is produced as well. Recall that formula units are equivalent to molecules as a unit. Al Hypothesis: State your strategy for how to solve the problem in 2-4 sentences. Note that this should
Fez
(Pou) ₂ + 3 C a F₂ → Caz CP0g) ₂ +3 FuFz
19.509
Mass of Callion floorle=
: 0.2497
Moles =
78.07
1 mol (az (PO4)2
3 mol Cafz
x 0.2497 mols CaF₂ = 0,0852
moles Сиз срои Ја
2
23
4.02 X 10
10.0832
Imola
5.012.10 22
= 0.5012 x 10²3
Transcribed Image Text:Fez (Pou) ₂ + 3 C a F₂ → Caz CP0g) ₂ +3 FuFz 19.509 Mass of Callion floorle= : 0.2497 Moles = 78.07 1 mol (az (PO4)2 3 mol Cafz x 0.2497 mols CaF₂ = 0,0852 moles Сиз срои Ја 2 23 4.02 X 10 10.0832 Imola 5.012.10 22 = 0.5012 x 10²3
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