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- One can prepare homemade lavender perfume by steam distillation. One of the main components in the lavender oil is linalyl acetate (MW 196 g/mol), which has a vapor pressure of approximately 20 mm Hg at the boiling point of the mixture with water. If one collects 500 g of lavender from a garden and performs a codistillation with water, what would be the composition of the distillate?The following equation describes the oxidation and ethanol to acetic acid by potassium permanganate 3C2H5OH+4KMnO4 —-> 3HC2H3O2 +4MnO2+4 KOH +H2O 5.00 g of ethanol and a excess of aqueous KMnO4 are reacted, and 5.24 g of HC2H3O2 result. What is the percentage yield? A. 100% B. 80.4% C. 26.8% D. 19.6%Fehling reagent I is prepared by dissolving 138.6 g of CuSO4·5H2O in 2 L H2O. The molecular weight of CuSO4·5H2O is 249.685 g/mole. Calculate the molarity of Fehling reagent I.
- b) % yield of ethanol from molasses (we used 50 mL of the molasses solvent for both distillation) c) % yield ethanol from sugars, assuming approximately half of molasses is reactive sugars C12H22O11 (sucrose) -> 4 CH3CH2OH + 4 CO2 my Simple distillation % ethanol was 100% (0.774) and my fractional distillation % ethanol was 100% (0.774).Cocaine (C17H21O4N) is a natural substance found in the leaves of the coca plant, which has been used for centuries as a local anesthetic and stimulant. Illegal cocaine arrives in the USA either as a pure compound or as the hydrochloride salt (C17H21O4NHCl). At 25oC, the salt is very soluble in water (2.50 kg/L), but pure cocaine is much less so (1.70 g/L). What is the maximum amount of salt (in gram) that can dissolve in 50.0 mL of water? [1 mark.] When a 25 mL aqueous solution that contains 62.50 g of the salt is treated with NaOH, the salt is converted to pure cocaine. How much water (in liters) is needed additionally to dissolve the formed pure cocaine? Round your final answer off to two decimal points. C17H21O4NHCl(aq) + NaOH(aq) → C17H21O4N(aq) + H2O(l) + NaCl(aq)Materials/Chemicals: Volumetric flasks Beakers Serologic pipetters Aspirators Vials/test tubes Cone. H3PO4 (85% w/w, sp gr. 1.70, MM 98) Cone. HCL (37.3% w/w sp. Gr. 1.18, MM 36) Glacial acetic acid (99.7% ww, sp gr. 1.05, MM 60) NaOH pellets NaH2PO4 Na2HPO4 Acid-base indicators: Bromophenol Blue Bromocresol green Phenol red Methyl red Methyl orange Phenolphthalein Thymol Blue pH paper pH meter Weighing balance For chemicals, refer from the template below. Research the chemicals to be used especially those that are new to you and write down the information needed. Name of Chemical Molec. Weight (g/mol) Melting point Boiling point Density (g/mL) General properties Methodolody: (Include a short summary of the overall experimental plan you are going to run. You may use flow chart or bullet form for this part. Sketches of any experimental set-ups used in the experiment or the workup procedures). Preparation of buffers Prepare 250ml of the…
- In the preparation of a standard stock solution for protein analysis, 50 mg of bovine serum albumin (BSA) was dissolved in deionized distilled water to a final volume of 10 mL. What is the weight of BSA in 0.60 mL stock solution?Calcium carbonate is used as an antacid to relieve heartbum, acid indigestion, and upset stomach. You have intake 6.088g CaCO3 with empty stomach and reacted with 2.852g Hydrochloric acid (HCl) present in the stomach. What mass of CaCO3 remains unreacted? Show the complete solution. CaCO3 +2HCl -> CaCl2 + CP2 +H2O a. What is the limiting reagent? b. What is the excess reagent? c. How much is leftover in the excess reagent?The ethyl acetate concentration in an alcoholic solution was determined by diluting a 10.00-mL sample to 100.00 mL. A 19.00-mL portion of the diluted solution was refluxed with 40.00 mL of 0.04601 M KOH: CH3 СОО С2H; + ОН — СH3 COO + C2H; ОН After cooling, the excess OH was back-titrated with 3.02 mL of 0.05056 M H2 SO4. Calculate the amount of ethyl acetate (88.11 g/mol) in the original sample in grams. Amount of ethyl acetate =
- Acetaminophen, a popular drug taken as pain reliever and fever reducer, is produced together with acetic acid from the reaction of 3.05 g 4-aminophenol and 4.1 ml of acetic anhydride. Acetaminophen was extracted at 60% yield. Density of acetic anhydride at 20 C, 1.08 g/ml. Calculate the actual no. of grams of acetaminophen produced. [Determine L.R., E.R.]Concentration of Reagents (NH4)2S2O8 KI Na2S2O3 0.25 M 0.22 M 0.19 M Volumes of Solutions S₂082 (mL) Starch soln (mL) KNO3 (mL) EDTA soln (mL) KI (mL) S₂O32- (mL) x 5 9.7 0.9 26.4 0.5 9.9 1.1 Using the above data determine the concentration of I at the moment the reaction begins. HINT: This is a mixing problem. Determine the total number of moles of I and divide this amount by the total volume (in L). Be careful... If you go back and try this exercise again the values will change. Read the question carefully! Answer:A 0.879 g sample of a CaCl2·2H2O/K2C2O4·H2O solid salt mixture is dissolved in ~100mL of deionized water. The precipitate, after having been filtered and air-dried, has a mass of 0.284 g. The limiting reactant in the salt mixture was later determined to beCaCl2 ·2H2O. a.Write the ionic equation for the reaction. b.Write the net ionic equation for the reaction. c.How many moles and grams of CaCl2 ·2H2O reacted in the reaction mixture? d.How many moles and grams of the excess reactant, K 2C2O 4H2O, reacted in the mixture? e.How many grams of the K2C2O4·H2O in the salt mixture remain unreacted (inexcess)? f.What is the percent by mass of each salt in the mixture