Calculate the gross allowable bearing capacity (q) for the foundation shown below Given: H = 5 ft B = 8 ft y = 100 lb/ft c' = 0 psf $ = 32° FS = 3.0 H
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Calculate the gross allowable bearing capacity (qall) for the foundation shown below
Given:
H = 5 ft
B = 8 ft
γ = 100 lb/ft3
c’ = 0 psf
φ = 32°
FS = 3.0
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- EXAMPLE-H.W. For the foundation shown in the below; estimate quantity of Reinforcement. Depth of foundation = 1.00 m, 5 0.5 m 16db 0 100 150 60db 20@2002. A square foundation mat supports the four columns shown. Determine the magnitude and point of application of the resultant of the loads. (R=?, x=? & z=?) 40 kips 12 kips 20 kips 8 kips C 5 ft 4 ft- 5 ft 6 ft. BGiven the following:Column: 600 mm x 600 mmAxial Dead Load = 1680 kNAxial Live Load = 1350 kNDepth of footing = 1.8 mAllowable soil pressure = 230 kPaUnit weight of soil above footing = 16 kN/m 3Unit weight of concrete = 24 kN/m 3fc' = 28 MPafy = 345 MPaDesign the footing if its width is limited to 3.2 m. Use 25 mm bars and 75 mm clear concrete cover. Useload factor of 1.4 DL + 1.7 LL.
- Q1: determine the increase in vertical stresses at depth of Z=3.5 m under points A, B and C due to apply rectangular and ring foundations. The surface load intensity of rectangular is 250 kN/m², while the surface load intensity of ring is 300 kN/m².The drawing was done without scale and all dimensions in (m). R1 R2 X1 X2 В L 3 4.5 7.5 6. 12 X1 X2 Aqs-net(2) R1 Aqs-net(1) R2Refer to Figure 5.2. Given: B = L = 1.75 m, Df = 1 m, H = 1.75 m, = 17 kN/m3, c = 0, and = 30. Using Eq. (5.6) and FS = 4, determine the gross allowable load the foundation can carry.Problem 1 A 300 mm x 400 mm column is to be supported by a 2 m x 2 m x 0.4 m thick footing @ its center. Service DL = 520 kN, service LL = 320 kN, CC to bar centroid is 90 mm, fc' = 21 MPa and fy = 414 MPa. %3D 300 400 300 400 Determine the critical wide beam shear stress. (Nominal and ultimate) Determine the critical punching shear stress. (Nominal and ultimate) Determine the required number of 20 mm ø bars parallel to the critical side.
- A square footing 2.5 m x 2.5 m supports a rectangular column 300 mm x 300 mm at its center. Concrete cover to bar centroid = 100 mm. Ultimate load combination is 1.2D + 1.6L. Column loads are service conditions: DL = 680 kN LL = 400 kN f’c = 20.7 MPa fy = 275 MPa Calculate the ultimate moment at critical section for bending for 1-m strip of the footing slab. = [Mu] kN·m/m (whole number) Answer: 141A piece of engineering equipment is supported by the foundation shown. The diameter of the circular pin is 20 mm. a.) Determine the value of P so as not to exceed the allowable bearing stress of 310.5 Mpa in the circular pin. b.) Determine the value of P so as not to exceed the allowable shearing stress of 138 Mpa in the circular pin.A piece of engineering equipment is supported by the foundation shown. The diameter of the circular pin is 20 mm. a.) Determine the value of P so as not to exceed the allowable bearing stress of 310.5 Mpa in the circular pin.b.) Determine the value of P so as not to exceed the allowable shearing stress of 138 Mpa in the circular pin.
- Q2: Compute the total stresses, which induced from geostatic stress and increase vertical stress from circular foundation under points A and B to 3 and 6 m depth from the base of the foundation. The foundation was constructed at 2.0 m below the natural ground level (NGL). The surface load intensity is 330 kN/m². R1= 4, (calculate R2 from the drawing, do not assume it). Assume any other parameter you need in your answer. Aqs netProblem.№₂3 - The plan of a mat foundation is shown in Figure. Calculate the soil pressure at points A, B, C, D, E, and F. (Note: All column sections are planned to be 0.5 m 3 0.5 m.) All loads shown are factored loads according to ACI 381-11 (2011). 550 KN 2000 KN 5.25 m 2000 KN 550 kN F *K 0.25 m G H 10 m ! B i 660 kN 2000 KN 10 m 2000 KN 660 kN E 600 KN 1600 KN 5.25 m 10 m 1600 KN 470 kN C D *K 0.25 m 9 m 9 m 9 m 0.25 m 0.25 mEXAMPLE For the foundation shown in the below; estimate quantity of Reinforcement. Depth of foundation = 0.7 m, cover = 7.5 cm $16/150 16db 60db $16/150 10 +12