Calculate the equilibrium constant for the reaction H (e) + Br (e) = HBr (3) 1. Given the following: H2 (e) + Br2 (e) = 2 HBr (g) K = 7.9 x 1011 H2 (2) = 2 H(e) K = 4.8 x 1041 Br2 (8) - 2 Br (8) K = 2.2 x 1015 1.

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter15: Principles Of Chemical Reactivity: Equilibria
Section: Chapter Questions
Problem 3PS: Kc = 5.6 1012 at 500 K for the dissociation of iodine molecules to iodine atoms. I2(g) 2 I(g) A...
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C.
remove carbon dioxide
right
left
no shift
d.
increase pressure
right
left
no shift
e.
add sodium carbonate
right
left
no shift
Calculate the equilibrium constant for the reaction
H (g) + Br (g) = HBr (g)
Given the following:
H2 (e) + Br2 (g) = 2 HBr (e)
K = 7.9 x 1011
H2 (B) = 2 H (8)
K = 4.8 x 10-41
Br2 (e) = 2 Br (e)
K = 2.2 x 1015
Transcribed Image Text:C. remove carbon dioxide right left no shift d. increase pressure right left no shift e. add sodium carbonate right left no shift Calculate the equilibrium constant for the reaction H (g) + Br (g) = HBr (g) Given the following: H2 (e) + Br2 (g) = 2 HBr (e) K = 7.9 x 1011 H2 (B) = 2 H (8) K = 4.8 x 10-41 Br2 (e) = 2 Br (e) K = 2.2 x 1015
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