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Calculate the concentration of an HCl solution if 100.0 mL of the HCl required 33.00 mL of 0.2000 M Mg(OH)2 to reach the titration endpoint. (Use stoichiometry, answer is 0.1320 M) Mg(OH)2 + 2 HCl ® 2 H2O + MgCl2

Calculate the concentration of an HCl solution if 100.0 mL of the HCl required 33.00 mL of 0.2000 M Mg(OH)2 to reach the titration endpoint. (Use stoichiometry, answer is 0.1320 M) Mg(OH)2 + 2 HCl ® 2 H2O + MgCl2

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 50QAP: Morphine, C17H19O3N, is a weak base (K b =7.4107). Consider its titration with hydrochloric acid. In...
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Calculate the concentration of an HCl solution if 100.0 mL of the HCl required 33.00 mL of 0.2000 M Mg(OH)2 to reach the titration endpoint. (Use stoichiometry, answer is 0.1320 M) Mg(OH)2 + 2 HCl ® 2 H2O + MgCl2

Calculate the concentration of an HCI solution if 100.0 mL of the HCI required 33.00 mL of 0.2000 M Mg(OH)₂ to reach the titration endpoint. Mg(OH)2 + 2 HCI → 2 H₂O + MgCl₂ There is enough information to calculate the moles of base but not the moles of acid. mol a. 0.1000 h. CaCO3(s) -1 0. H₂PO41 v. H₂CO3 bb. 3.300 x 10-² hh. 2.16 x 10-6 b. 0.1320 i. OH-1 -2 p. CO32 W. PO4³ -3 L)(- mol Mg(OH)3)(- mol HCI c. HX j. H30+1 q. HCO3-1 x. HC₂H3O2 dd. 2 jj. 0.2000 d. Al+3 k. SO4 CC. 3 ii. 1.60 x 10-5 -2 r. H₂S e. CO₂ -) = y. C₂H30₂-1 ee. 1 I. Mg+2 s. HS-1 mol HCI mol Mg(OH)2 M HCI f. CaF2(aq) m. Cl-1 t. 5-² z. 1 x 10-14 ff. 0.099536 kk. 6.600 x 10-³ g. HF (aq) n. HPO4² u. H₂O(liq) mol Mg(OH)3 aa. 1.32 x 102 gg. 3.95 x 10-3 mol HCI
Transcribed Image Text:Calculate the concentration of an HCI solution if 100.0 mL of the HCI required 33.00 mL of 0.2000 M Mg(OH)₂ to reach the titration endpoint. Mg(OH)2 + 2 HCI → 2 H₂O + MgCl₂ There is enough information to calculate the moles of base but not the moles of acid. mol a. 0.1000 h. CaCO3(s) -1 0. H₂PO41 v. H₂CO3 bb. 3.300 x 10-² hh. 2.16 x 10-6 b. 0.1320 i. OH-1 -2 p. CO32 W. PO4³ -3 L)(- mol Mg(OH)3)(- mol HCI c. HX j. H30+1 q. HCO3-1 x. HC₂H3O2 dd. 2 jj. 0.2000 d. Al+3 k. SO4 CC. 3 ii. 1.60 x 10-5 -2 r. H₂S e. CO₂ -) = y. C₂H30₂-1 ee. 1 I. Mg+2 s. HS-1 mol HCI mol Mg(OH)2 M HCI f. CaF2(aq) m. Cl-1 t. 5-² z. 1 x 10-14 ff. 0.099536 kk. 6.600 x 10-³ g. HF (aq) n. HPO4² u. H₂O(liq) mol Mg(OH)3 aa. 1.32 x 102 gg. 3.95 x 10-3 mol HCI
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