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Calculate the change in energy for the following processes:
Ca(g) + 2 Br(g) -> Ca2+(g) + 2 Br-(g)
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- Determine the second ionization energy of calcium (in kJ mol-1) from the given data (all in kJ mol-1): AH°[CaCl,(s)] = -796 AH¡[Ca(g)] = 178 AH°[CI(g)] = 122 First ionization energy of Ca(g) = 590 Electron affinity of Cl(g) = -349 Lattice enthalpy of CaCl,(s) = -2260 А 1150 В 1235 C 1093 D 1210Use Born-Mayer equation to calculate the lattice energy for PbS (it crystallizes in theNaCl structure). Then, use the Born–Haber cycle to obtain the value of lattice energy for PbS.You will need the following data following data : ΔH Pb(g) = 196 kJ/mol; ΔHf PbS = –98kJ/mol; electron affinities for S(g)→S- (g) is -201 kJ/mol; ) S- (g) →S2-(g) is 640kJ/mol. Ionizationenergies for Pb are listed in Resource section 2, p.903. Remember that enthalpies of formationare calculated beginning with the elements in their standard states (S8 for sulfur). Diatomicsulfur, S2, is formed from S8 (ΔHf: S2 (g) = 535 kJ/mol. Can you just do the Born-Haber part?Consider a hypothetical ionic compound AB (comprised of A* and B ions). Given the following enthalpy data and using a Born-Haber cycle calculation, predict AHiattice in kJ mol. AG) + Bs) - AB 4H = -384 kJ mol As) → Ag) ArH = 105 kJ mol B(s) - Bg) A,H = 101 kJ mol1 First ionization energy of Ag) = 501 kJ mol" Answes=? Electron affinity enthalpy of Bro (exothermic) = -348 kJ mol
- Given the following information, construct a Born-Haber cycle to calculate the lattice energy of CrCl₂I(s): Net energy change for the formation of CrCl₂I(s) = -420 kJ/mol Bond dissociation energy for I2(g) = +243 kJ/mol Bond dissociation energy for Cl2(g) for Cl2(g) for 12(g) = +151 kJ/mol Heat of sublimation for I2(s) = +62 kJ/mol Heat of sublimation for Cr(s) = +397 kJ/mol = E₁₁ for Cr(g) = 652 kJ/mol E₁₂ for Cr(g) == 1588 kJ/mol E₁3 for Cr(g) = 2882 kJ/mol Eea for Cl(g)=-349 kJ/mol === Eea for I(g) = -295 kJ/mol11)Explain the given ionization energy for each pair using electron configurations. (12(Be)l1(B), I1(N)>l1(O) ).The standard formation enthalpy of KCl is -571 kJmol-1. Plot the Born-Haber cycle and calculate the electron affinity of chlorine with the help of the data below. ΔH ° a (K) = 89 kJmol-1 BE (Cl-Cl) = 244 kJmol-1 IE (K) = 425 kJmol-1 ΔHL (KCl) = 719 kJmol-1
- Using the following thermodynamic data, calculate the lattice enthalpy of lithium oxide: Li(g) → Li*(g) + e* AH₁= 540 kJ /mol Li(s) → Li(g) AHS= +146 kJ/mol O₂(s) → 20(g) AH₂= +488 kJ /mol O(g) + 1e →→ O(g) AHA1= -142 kJ /mol O` (g) + 1e¯ → 0²-(g) AHÃ₂= +844 kJ /mol 2Li(s) + 1/2O₂(g) → Li₂O(s) AH₁= -586 kJ /mol NOTE: Give your answer in kJ mol-¹5. Which of the following alkali metal halides has the larger lattice energy, and which has the smaller lattice energy? Explain. (a) (b)Consider the following data for palladium: g mol atomic mass electronegativity ionization energy 106.42 electron affinity 53.7 heat of fusion 2.20 804.4 16.7 kJ mol kJ mol kJ mol Does the following reaction absorb or release energy? (1) Pd (g) Pd (g) + e Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (1): Does the following reaction absorb or release energy? (2) Pd (g) + e Pd (g) Is it possible to calculate the amount of energy absorbed or released by reaction (2) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (2): O release O absorb O Can't be decided with the data given. O yes no kJ/mol O release O absorb O Can't be decided with the data given. O yes no kJ/mol
- 1) Calculate the lattice energy for NaCl(s) using a Born-Haber cycle and the following information: NaCl(s) → Nat(g) + Cl-(g) Na(s) + 1/2 C12(g) → NaCl(s) Na(s) → Na(g) Na(g) → Na+(g) + e- 1/2 C12(g) → Cl(g) Cl(g) + e- → Cl-(g) ? -411.0 kJ/mol +107.3 kJ/mol +495.8 kJ/mol +121.7 kJ/mol -348.6 kJ/mol4. The common oxidation number for an alkaline earth metal is +2. (a) Using the Born-Mayer equation (for determining the lattice enthalpy) and a Born-Haber cycle (draw it), show that CaCl is an exothermic compound (negative AHf). Make a reasonable prediction to estimate the ionic radius of Ca (explain your reasoning). The sublimation (atomization) enthalpy for Ca(s) is 178 kJ/mol. (b) Show that an explanation for the non-existence of CaCl can be found in the enthalpy change for the reaction below. The AHf for CaCl2(s) is -190.2 kcal/mol. 2 CaCl(s) → Ca(s) + CaCl2(s)The standard formation enthalpy of KCl is -571 kJmol-1. Plot the Born-Haber cycle and calculate the electron affinity of chlorine with the help of the data below. ΔH°a(K) = 89 kJmol-1 BE(Cl-Cl) = 244 kJmol-1 IE(K) = 425 kJmol-1ΔHL(KCl) = 719 kJmol-1