Calculate AH for the reaction C6H6(l) + (15/2)0₂(g) →→→ 6CO2(g) + 3H₂O(l) using the following thermochemical equations: 6C(graphite) + 3H₂(g) → C(graphite) + O₂(g) → H₂(g) + (1/2)O₂(g) C6H6(1): AH = +49.0 kJ CO₂(g): AH = -393.5 kJ H₂O(l): AH = -285.8 kJ

Calculate AH for the reaction C6H6(l) + (15/2)0₂(g) →→→ 6CO2(g) + 3H₂O(l) using the following thermochemical equations: 6C(graphite) + 3H₂(g) → C(graphite) + O₂(g) → H₂(g) + (1/2)O₂(g) C6H6(1): AH = +49.0 kJ CO₂(g): AH = -393.5 kJ H₂O(l): AH = -285.8 kJ

General Chemistry - Standalone book (MindTap Course List)

11th Edition

ISBN:9781305580343

Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell

Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell

Chapter6: Thermochemisty

Section: Chapter Questions

Problem 6.94QP

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Applications of Molecular Spectroscopy

When light sources pass through the diffraction grating then light splits into different wavelengths. The light source produces two types of patterns that are shown as destructive and non-destructive. The light source is in the form of quanta that is quantitation.

Question

Calculate AH for the reaction C6H6(l) + (15/2)02(g) 6CO2(g) + 3H₂O(l) using the following
thermochemical equations:
6C(graphite) + 3H₂(g)
C(graphite) + O₂(g)
H₂(g) + (1/2)02(g) →
C6H6(1): AH = +49.0 kJ
CO₂(g): AH = -393.5 kJ
H₂O(l); AH = -285.8 kJ

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