Calculate AG for the reaction 2 H₂S(g) + 5O₂(g) =3 Srhombic(s) + 2 H₂O(g) For the following conditions at 25°C: PH₂S=0.0003 atm Pso₂=0.0289 atm PH₂0=0.0157 atm AG = AG ºf H₂S(g) = -34 kJ/mol SO₂(g) = -300. kJ/mol H₂O(g) = -229 kJ/mol kj

Chemistry & Chemical Reactivity
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ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section18.5: Entropy Changes And Spontaneity
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Calculate AG for the reaction
2 H₂S(g) + 5O₂(g) =3 Srhombic(s) + 2 H₂O(g)
For the following conditions at 25°C:
PH₂S=0.0003 atm
Pso₂=0.0289 atm
PH₂0=0.0157 atm
AG =
AG ºf
H₂S(g) = -34 kJ/mol
SO₂(g) = -300. kJ/mol
H₂O(g) = -229 kJ/mol
kj
Transcribed Image Text:Calculate AG for the reaction 2 H₂S(g) + 5O₂(g) =3 Srhombic(s) + 2 H₂O(g) For the following conditions at 25°C: PH₂S=0.0003 atm Pso₂=0.0289 atm PH₂0=0.0157 atm AG = AG ºf H₂S(g) = -34 kJ/mol SO₂(g) = -300. kJ/mol H₂O(g) = -229 kJ/mol kj
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