Calculate a value for the equilibrium constant for the reaction O2 (9) + O(g) = 03 (g) given hv NO2 (g) = NO(g) + O(g) K = 5.1 × 10-49 03 (g) + NO(9) = NO,(g)+ O2(9) K= 2.2 × 10-34 (Hint: When reactions are added together, the equilibrium expressions are multiplied.) K=

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Chapter13: Chemical Equilibrium
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Problem 13Q: Suppose a reaction has the equilibrium constant K = 1.3 108. What does the magnitude of this...
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Calculate a value for the equilibrium constant for the reaction
O2 (g) + O(g) = 03 (9)
given
hv
NO2 (g) = NO(g) + O(g) K = 5.1 × 10-49
-34
O3 (g) + NO(g)= NO,(g) + O2(g) K = 2.2 × 10-
(Hint: When reactions are added together, the equilibrium expressions are multiplied.)
K =
Transcribed Image Text:Calculate a value for the equilibrium constant for the reaction O2 (g) + O(g) = 03 (9) given hv NO2 (g) = NO(g) + O(g) K = 5.1 × 10-49 -34 O3 (g) + NO(g)= NO,(g) + O2(g) K = 2.2 × 10- (Hint: When reactions are added together, the equilibrium expressions are multiplied.) K =
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