C9 x 15 2 in 4 in 2늘 in 2 in 3 in 3 in in Ø bolts

Q: The two C15 X 40s shown in Figure below have been selected to supporta dead tensile working load of…

A: Solution Given Data Dead Tensile working load= 130k Live Tensile Working Load= 250k Member length…

Q: Determine the smallest net area of the tension member shown in Fig. P3-17.The holes are for 3/4-in Ø…

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Q: 3. Determine the LRFD design tensile strength and the ASD allowable tensile strength for an A36 (Fy=…

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Q: Determine the LRFD design strength and the ASD allowable strength of the sections with longitudinal…

A: Given, A572 Grade 42 Steel Fy=42 ksiFu=60 ksi

Q: USING LRFD, DETERMINE THE ff: 1. LOAD P that the angles can carry against tensile yielding in the…

A: Given : Breadth of the plate, B = 200 mmThickness of the plate, t = 10 mmDiameter of bolts, d = 20…

Q: Determine the effective net area of the W16 x 40 shown in Fig. P3-23. Assume the holes are for…

A: Given: W16×40. From the properties, Ag=118 in2.tf=0.505 in.bf=7 in.d=16 in

Q: Determine the LRFD design strength and the ASD allowable strength sections given. Neglect block…

A: Given section

Q: A single-angle tension member 175 mm x 100 mm x 18 mm haw two gage lines in its long leg and one in…

A: Area of the angular section(A)=4961 mm2, Tension member=175mm x 100mm x 18 mm, Fy=248 Mpa, Fu=400…

Q: Find the available strength of the S-shape shown. The holes are for ¾-in diameter bolts. Use A36…

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Q: Design of Tension Members. Determine the LRFD design strength and the ASD allowable strength of…

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Q: The W24x76 beam has holes for 11/2in diameter bolts in the top and bottom flanges as shown.…

A: The diameter of the hole is dh=112 in.  The standard values or properties of W 24x76 beam are as…

Q: Determine the LRFD design strength and the ASD allowable strength of the W16x31 shown including the…

A: Given  W16×31  and Grade of steel = A992 for A992 steel,   yield stress Fy = 50 ksi, ultimate stress…

Q: The tension member shown in Fig. P3-13 contains holes for 3/4-in Ø bolts. At what spacing, s, will…

A: To Find :- Pitch S between the staggered bolts

Q: Determine the LRFD design strengths ØP and the ASD allowable strengths P/f of the following section…

A: Answer (a) Fy =345 Mpa, Fu = 450 Mpa Bolt = 22mm  tf = 11.18 mm We know that Nominal block shear…

Q: Problem 05 -L7x 4 x을 Use A36 steel and 3/4-in Ø bolts 3 in 24 in 3 in 1 tt t - 2 in

A: Tensile strength is the dimension of the amount of force acting on a particle to pull.  LFRD is to…

Q: 2 in 3 in ... Determine the LRFD design strength and the ASD allowable strength of sections given.…

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Q: The built-up section shown in Fig. P3-8 for which -in Ø bolts are used. PL를 x 14 WT15 x 45

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Q: Q3) Determine the total number of 3/4-inch, A325 bolts required for the tension splice in Figure.…

A: Solution

Q: 6.2 The vertical steel bar shown is 3/8 in. thick and must be designed to withstand a tensile load…

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Q: Compute the net area of each of the given members.

A: For,WT 15×54,overall depthh=14.9 inwidth of flangeb=10.5 inthickness of flange(tf)=0.76 inthickness…

Q: A C12x30 is connected with 1-inch diameter bolts in each flange (see below). The steel is A572…

A: Given data:

Q: Compute the net area of each of the given members. The built-up section shown in Fig. P3-8 for which…

A: Refer to AISC table 1-8  Section properties of the member WT15×45 The area of the member AWT is 7.07…

Q: GIVEN:  PL ⅜ x 5 ½ of A242 steel ⅜ - inch thick gusset plate A242 steel ¾ - inch diameter bolts…

A: Compressive stress is the force that deforms the material in a way that reduces the volume of the…

Q: Determine the LRFD design strength and the ASD allowable strength of the sections given, including…

A: ASD: It applies service load to the structure. It evaluates forces and stress using linear…

Q: A C12 × 30 is connected with 1-in. diameter bolts in each flange, as shown in Figure P3.2-3. If Fy =…

A: The design strength is reduction in the actual resistance of the member while considering the factor…

Q: Determine the LRFD design tensile strength and the ASD allowable tensile strength for the member and…

A: Solution: Considering the above given diagram. Compute gross section yielding of plates :…

Q: 2C10 x 20, of A572 grade 50 steel ½ - inch - diameter bolts REQUIRED: The total service load…

A: Given:- Two C10 x 20 channels are given The diameter of the bolts = ½ - inch The live load is 3…

Q: 3-21./ Determine the effective net area of the L8 X 4 x ½ shown in Fig. P3-21. Assume the holes are…

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Q: 4. Determine the LRFD design strength and the ASD allowable strength of sections given. Neglect…

A: Given, Section = L7×4×12 Hence, t=0.5 inch A36 steel Diameter of the bolt=12 inch Diameter of the…

Q: Problem 1: For the WT8x50 attached through the flange to a 12x34 inch plate with eight 7/8 inch…

A: Solution: Given: Section: WT 8 x 50 A = 14.70 in2 y = 1.760 in bolt = 7/8 in s = 3 in

Q: Determine the effective net area of the L7 x 4 x1/2 shown in Fig. P3-21. Assume the holes are for…

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Q: A C12 × 30 is connected with 1-in. diameter bolts in each flange, as shown. If Fy = 50 ksi, Fu = 65…

A: Given- Fy= 50 ksiFu =65 ksi Ae = 0.90An

Q: GIVEN: WT8 x 13 of A992 steel ⅞-inch diameter bolts   REQUIRED:  The nominal block shear…

A: Given data, WT8 x 13 of A992 steel ⅞-inch diameter bolts Fu = 65 ksi Fy = 50 ksi The section…

Q: Question 3: Four 3 x 3 x1/2 angles are used to form the member shown in the accompanying…

A: Design the end tie plates and lacing bars as shown belowDraw thr cross section of the column as…

Q: 3) Determine the number of M24 Grade 10.9 bolts required to develop full yielding capacity of the…

A: Solution: Given: UPN 300 member: h = 380 mm, A = 5880 mm2, tw = 10 mm M24 bolts, d = 24 mm do = 26…

Q: Select the lightest WT7 available to support a factored tensile load P₁ = 250 k, Pa = 160 k. Assume…

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Q: A WT6X26.5, A992 steel, attached through the flange with 1-in Ø bolts as shown. WT6 × 26.5 5 in 1 in…

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Q: Problem 01 Select the lightest W12 section available to support working tensile loads of Po = 120 k…

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Q: 2 in Ø bolts W12 × 40-

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Q: 4. Select the lightest W14 section available to support service tensile loads Po = 445KN and P = 667…

A: Introduction- When a structure, or any member or element, is subjected to acceptable combinations of…

Q: A W18 × 35 with two holes in each flange and one in the web, all for 7/8-in Ø bolts. Compute the net…

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Q: An angle with staggered fasteners in each leg is shown in Figure 3.17. A36 steel used, and holes are…

A: An angle with staggered fasteners in each leg is shown in Figure. A36 steel is used, and holes are…

Q: A double angle shape, 2 L 100 x 75 x 6 (LLBB), of A36 steel (Fy = 248 MPa and Fu = 400 MPa) is used…

A: “Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

Q: The two C12 x 30sshown in Fig. 4.2 have been selected to support a dead tensile working load of 120…

A: Solution: Given: Section C122 x 30 Ag = 8.81 in2 d = 12 in tw = 0.51 in tf = 0.501 in Ix = 162 in4…

Q: Q3) Determine the total number of 4-inch, A325 bolts required for the tension splice in Figure. The…

A: The given figure is shown below:

Q: tension member

A:

Q: Compute the effective net area of the built-up section shown in Fig. P3-19 if the holes are punched…

A: Calculation of net area (An): The given member of C10x25 is given below:

Q: Determine the LRFD design strength and the ASD allowable strength . Neglect block shear. A WT8 x 50…

A: Given, WT 8 * 50 of A992 steel: Fy = 50 ksi Fu = 65 ksi 2 lines of 7/8 in dia bolts, 4 in a line and…

Q: 3.6-3 Select a double-angle tension member to resist a service dead load of30 kips and a service…

A: LRFD