C3H8 (g) +502(g) → 3CO2 (g) +4H₂O(g) AHxn=-2044 kJ Spontaneous at all temperatures 2N2(g) + O2(g) →2N₂O(g) AHxn= +163.2 kJ Spontaneous at high temperatures 4NH3(g) + 502(g) → 4NO(g) + 6H₂O(g) AHxn-906 kJ Spontaneous at low temperatures Nonspontaneous at all temperatures

Chemistry for Engineering Students
4th Edition
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Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter10: Entropy And The Second Law Of Thermodynamics
Section: Chapter Questions
Problem 10.50PAE: For the reaction NO(g)+NO2(g)N2O3(g) , use tabulated thermodynamic data to calculate H and S. Then...
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Part C
In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction is spontaneous.
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C3H8 (g) + 50₂(g) →
3CO2 (g) + 4H₂O(g)
AHxn=-2044 kJ
Spontaneous at all
temperatures
2N₂(g) + O₂(g) →2N₂O(g)
AHxn = +163.2 kJ
Spontaneous at high
temperatures
Previous Answers Request Answer
4NH3 (g) +502(g) →
4NO(g) + 6H₂O(g)
AHixn = -906 kJ
Spontaneous at low
temperatures
Reset Help
Nonspontaneous at all
temperatures
Transcribed Image Text:Part C In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction is spontaneous. Drag the appropriate items to their respective bins. Submit C3H8 (g) + 50₂(g) → 3CO2 (g) + 4H₂O(g) AHxn=-2044 kJ Spontaneous at all temperatures 2N₂(g) + O₂(g) →2N₂O(g) AHxn = +163.2 kJ Spontaneous at high temperatures Previous Answers Request Answer 4NH3 (g) +502(g) → 4NO(g) + 6H₂O(g) AHixn = -906 kJ Spontaneous at low temperatures Reset Help Nonspontaneous at all temperatures
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