C programming Input code in "Enter code here" section
C
Input code in "Enter code here" section
![#include <stdio.h>
void matrix_printer( ... ){
printf("MatrixA \t MatrixB\n");
// Enter code here
printf("\n");
void matrix_operation( ... ){
printf("\nResult\n");
// Enter code here
}
int main(){
int matrixA[4][4];
int matrixB[4][4];
char operator;
// Enter code here
printf("\n");
getchar();
matrix_printer (matrixA, matrixB);
printf("Enter operator (+, -): ");
do{
scanf ( "%c", &operator);
}while(operator != '+' && operator != '-');
matrix_operation(matrixA, matrixB, operator);
return 0;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F300b1fc5-2fff-487f-af38-550515adf9e8%2F0122f51f-ef9b-41de-96d3-9f8240d7e6b1%2Fcdec9k_processed.png&w=3840&q=75)
Approach
Function matrix_printer
void matrix_printer(int matrixA[][4], int matrixB[][4]) {
printf("MatrixA \t MatrixB\n");
for (int c = 0; c < 4; c++) {
for (int d = 0 ; d < 4; d++) {
//print matrixA elements
printf("%d ", matrixA[c][d]);
}
printf("\t");
for (int e = 0 ; e < 4; e++) {
//print matrixB elements
printf("%d ", matrixB[c][e]);
}
printf("\n");
}
printf("\n");
}
Function matrix_operation
void matrix_operation(int matrixA[][4], int matrixB[][4], char operator) {
printf("\nResult\n");
int matrixC[4][4];
int c,d;
if (operator == '+') //check if operator is '+'
{
for (c = 0; c < 4; c++) {
for (d = 0 ; d < 4; d++) {
matrixC[c][d] = matrixA[c][d] + matrixB[c][d]; //perform addition
printf("%d ", matrixC[c][d]); //print result
}
printf("\n");
}
}
if (operator == '-') //check if operator is '-'
{
for (c = 0; c < 4; c++) {
for (d = 0 ; d < 4; d++) {
matrixC[c][d] = matrixA[c][d] - matrixB[c][d]; //perform subtraction
printf("%d ", matrixC[c][d]); //print result
}
printf("\n");
}
}
}
Step by step
Solved in 2 steps with 2 images
