Blows Moisture Content,%
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Q: LIQUID LIMIT TEST Moisture content (%) 42.5 47.5
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Q: oplied for dry soil, except: a) Sre = wGs b) Gspw /1+ e c) Ms / V d) P,/1+ w
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Q: Dry Density (&) Optimum Moisture Content (OMC)
A: Density =Weight of soilVolume of moldDry density =Denisty1+w
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- Plastic Limit Test: Weight of wet soil + container = 22.12 g Weight of dry soil + container = 21.42 g Weight of container = 13.07 g Natural Water Content Test: Weight of wet soil + container = 17.53 g Weight of dry soil + container = 14.84 g Weight of container = 7.84 g a.) Compute the liquid limit. (Tip: Use normal scale) b.) Compute the plastic limit. c.) Compute the natural water content. d.) Compute the plasticity index. e.) Compute the liquidity index. d.) Compute the consistency index.SITUATION 2: From the following data of a given sieve analysis: Sieve No. # 4 Opening Percent (mm) 4.76 2.38 2.0 0.71 0.25 0.149 0.074 passing 90 #8 #10 #25 # 60 #100 # 200 64 58 30 22 10 4 9. Determine size(D10). а. 0.20 с. 2.0 10. Determine Cu. а. 10 C. 20 the effective grain b. 0.15 d. 0.09 b. 15 d. 5Find the piasticity index %, if the liquid lim't is 55.96% and plastic limit 27.51 % 28 50 O 28.10 O 28 40 O 28 45 O
- SITUATION 3. Following are the results of a sieve analysis. SIEVE NO. OPENING (mm) RETAINED 4 4.75 10 2.0 40 20 0.85 60 40 0.425 89 60 0.25 140 80 0.18 122 100 0.15 210 200 0.075 56 PAN 12 a. Find the effective particle size. b. Determine the uniformity coefficient. c. Find the coefficient of curvature.The data from a standard Proctor test are shown in the table below.a. Determine the maximum dry unit weight and the optimum water content.b. Plot the zero air voids line.c. Determine the degree of saturation at the maximum dry unit weight.Diameter of mold 101.4 mmHeight of mold 116.7 mmMass of mold 4196.50 gramsSpecific gravity, Gs 2.722A. Find Liquid Limit B. Find Plastic Limit C. Plasticity Index D. Liquidity Index
- The back fill material for a vibroflotation project has the following grain sizes. D10 0.11 mm Calculate the sorting coefficient. 2.798 Select the correct response: 1.633 D20 3.546 0.20 mm 1.581 D50 1.3 mm D25 0.60 mm D75 1.60 mm(a) A particular soll sample was run thru a stack a sieves and the data shown below was obtained. Find the hydraulic conductivity in (1) gpd/12 (2) m/day (b) This method of estimating K is sufficient for some purposes, but does not glve an accurate figure of the soll's true hydraulic conductivity, even when weighing errors and graphing errors are considered. 10. Why? Cumulative Cumulative weight in grams Pan # # 6 # 8 8. # 12 54 # 16 99 # 20 166 # 40 215 #70 224 Pan 238Q2: The dial readings recorded during a consolidation test at a certain load increment are given below. Determine c, by both the square root of time and log of time methods. The thickness of the sample = 2 cm and the sample is drained both sides. Time Dial Reading Time min Dial Reading cm x 10-4 min cm x 10-4 0 240 15 622 0.10 318 H 30 738 C₁=0.848- 0.25 340 60 842 0.50 360 120 930 1.00 385 240 975 2.00 415 1200 1070 C,=0.197 4.00 464 8.00 530 90 H² tso
- 1. Fineness modulus of the aggregate Weight Retained Individual Cumulative Percent Sieve (g) Percent Percent Passing 4.75mm 31.5 2.36mm 67.6 1.18mm 96.5 600um 111.1 300um 60.5 150um 115.6 75um 17.5 pan 31.5 O a. 2.96 O b. 2.76 O c. 2.54 O d. 2.34SHOW COMPLTE SOLUTION AND THE ANSWERS SHOULD BE IN 4 DECIMAL PLACES.I'LL RATE, TY Given the laboratory results of the Atterberg Limits Test in the following figure, plot the water content versus the number of blows. Determine the ff. ( PLS SHOW COMPLETE SOLUTION AND GRAPH ) A. Determine the nearest value to the Liquid Limit of soil.B. Determine the nearest value to the Plastic Limit of soil.C. Determine the nearest value to the Liquidity Index of soil.Q2. Caleculate the CBR value for the laboratory data in the table. Load (kn) Mold Mold Mold 3 Penetration (mm) 2 2.5 0.7 1.3 2.2 5.0 1.13 1.7 2.9