Below is an IPO program which allows the user to find out how many Euros she will get for a given number of dollars. Sometimes, the user enters an invalid value, like $30. Use validation along with the loop-and-a-half sentinel pattern to complete this problem.
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Types of Loop
Loops are the elements of programming in which a part of code is repeated a particular number of times. Loop executes the series of statements many times till the conditional statement becomes false.
Loops
Any task which is repeated more than one time is called a loop. Basically, loops can be divided into three types as while, do-while and for loop. There are so many programming languages like C, C++, JAVA, PYTHON, and many more where looping statements can be used for repetitive execution.
While Loop
Loop is a feature in the programming language. It helps us to execute a set of instructions regularly. The block of code executes until some conditions provided within that Loop are true.
Below is an IPO program which allows the user to find out how many Euros she will get for a given number of dollars. Sometimes, the user enters an invalid value, like $30. Use validation along with the loop-and-a-half sentinel pattern to complete this problem.
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- 1#include 2 #include #include 4 #include 3 5 sem_t fork[3]; 6 7 void eat (int phil) { 8 printf("Philosopher %d is eating\n", phil); sleep (2); //time eating 9 10} 11 void philosopher (void * num) { int phil-*(int *)num; 12 13 printf("Philosopher %d wants to eat\n", phil); 14 sem_wait (&fork[phil]); 15 sem_wait (&fork [(phil+1)]); 16 eat (phil); 17 18 printf("Philosopher %d has finished eating\n",phil); sem_post(&fork [(phil+1)]); sem_post(&fork[phil]); 19 20} 21 int main(){ 22 int i, a[3]; 23 pthread_t tid[3]; for(i=0;i<3; i++) 24 25 sem_init(&fork[i],0,1); 26 for(i=0;i<3; i++){ 27 a[i]=i; 28 pthread_create(&tid[i], NULL, philosopher, (void *)&a[i]); 29 } 30 for(i=0;i<3;i++) 31 pthread_join(tid[i],NULL); 32} Fig.1 Figure 1 shows a program that tries to solve the dining philosophers' problem given that it only includes 3 philosophers who want to eat, where only 3 forks are available and each philosopher needs two forks. The outputs after running the program are given in Figure 2. In the…#include #include #include "Product.h" using namespace std; int main() { vector productList; Product currProduct; int currPrice; string currName; unsigned int i; Product resultProduct; cin>> currPrice; while (currPrice > 0) { } cin>> currPrice; main.cpp cin>> currName; currProduct.SetPriceAndName (currPrice, currName); productList.push_back(currProduct); resultProduct = productList.at (0); for (i = 0; i < productList.size(); ++i) { Type the program's output Product.h 1 CSE Scanned Product.cpp if (productList.at (i).GetPrice () < resultProduct.GetPrice ()) { resultProduct = productList.at(i); } AM cout << "$" << resultProduct.GetPrice() << " " << resultProduct. GetName() << endl; return 0; Input 10 Cheese 6 Foil 7 Socks -1 Output== include using namespace std; # int main () { int a = 14; do { if( a 15) { a = a + 1; } cout << a <<" "; a = a + 1; } while( a < 16 ); } الجواب: إجابة
- QUESTION 21 int x1=200; int y1=3003; int z1, z2, z3, z4; int d1, d2, d3; _asm{ mov EAX, x1; 200 mov EBX, y1; 300 mov z1, ESP; assume initial ESP: OFFF FFEA add EAX, x1; 400 push EAX; mov d1, EAX:400 mov z2, ESP; push EBX; SUB EBX, x1; 300-200=100 mov d2, EBX; mov 23, ESP; POP ECX; MOV d3, ECX; MOV z4, ESP; POP EDX; mov d4, EDX; What is z3 in Hexidecimal? O OFFF FFEA O OFFF FFE6 OFFF FFE2 OFFF FFEE#include <iostream>#include <string>#include <iomanip>using namespace std;// structurestruct Hat{string brand;string color;float price;};// Customer structurestruct Customer{string fullName ;int age ;Hat hat; // Hat structure (nested in Customer)};int main(){// declare 5 variables of CustomerCustomer customer_1,customer_2,customer_3,customer_4,customer_5;cout<<"Welcome to Hats For U!\n";cout<<"Customer 1\n";cout<<"Enter customer's Full Name: ";getline(cin,customer_1.fullName);cout<<"Enter customer's age: ";cin>>customer_1.age;cout<<"Enter the brand of hat: ";cin>>customer_1.hat.brand;cout<<"Enter the hat color: ";cin>>customer_1.hat.color;cout<<"Enter the hat price(RM): ";cin>>customer_1.hat.price; cout<<"Hat 2\n";cout<<"Enter customer's Full Name: ";getline(cin,customer_2.fullName);getline(cin,customer_2.fullName);cout<<"Enter customer's age:…#include <stdio.h>#include <string.h> struct user { char user_name[10]; char bank_name[10]; int account_num[4]; int card_number[14]; int pass[4]; int balance; int wallet_num[11];}; int num_acc;int withdrawal;int deposition;char transaction;int k;int number_of_papers;int choice4; void print_array(int arr[], int size){ for (int i = 0; i < size; i++) { printf("%d", arr[i]); } printf("\n");} void print_struct(char username[], char bankname[], int accountnum[], int size3, int cardnum[], int size4, int balance){ printf("Username is %s", username); printf("\nBankname is %s\n", bankname); printf("Account number is "); print_array(accountnum, size3); printf("Cardnumber is "); print_array(cardnum, size4); printf("Balance is %d\n", balance);} void scan_array(int arr[], int size){ for (int i = 0; i < size; i++) { scanf_s("%d", &arr[i]); } } int search_name_in_array(struct user user[], int size1, char…
- struct Player { string firstName; string lastName; int hits; int runs; }; int main() { Player p = { "Jackie", "Robinson", 1518, 947 }; Player team[24]; Player *tPtr = team; team[0] = p; // INSERT CODE HERE } The statement tPtr = team+9; will assign the same memory address to tPtr as the statement tPtr = &(team[9]);#include<iostream>#include<string.h>using namespace std; struct student{ int number; string name; int age; string city;}s[10]; struct module{ int number; string name; string code; int credit;}m[10]; struct assessment{ int number; int marks1; int marks2;}a[10]; int index1 =0, index2=0, index3=0; void StudentRegistration(){ if(index1==10) { cout<<"No more data can be added"<<endl; return; } string temp; cout<<"Enter personal data"<<endl; cout<<"Enter Student Number"<<endl; cin>>s[index1].number; cout<<"Enter Student Name"<<endl; getline(cin, temp); getline(cin,s[index1].name); cout<<"Enter Age"<<endl; cin>>s[index1].age; cout<<"Enter city"<<endl; getline(cin,temp); getline(cin,s[index1].city); index1++;} void ModuleEnrolment(int id){ if(index2==10) { cout<<"No more data can be…snack.h #include <string>#include <iostream>#include <vector>class Snack{public:Snack(std::string, float, bool);int set_price(float);void set_expired(bool);void set_name(std::string);std::string name() const{return name_;}float price() const{return price_;}bool expired() const{return expr_;}int how_many_for_ten();private:std::string name_;float price_;bool expr_;};void SortByPrice(std::vector<Snack>&,bool); main.cpp #include <iostream>using namespace std; #include "snack.h" int main(){ Snack snicker=Snack("Snickers",2.0,false); std::cout<<snicker.name()<<" "<<snicker.price()<<" "<<snicker.expired()<<std::endl; Snack twix=Snack("Twix",3.0,false); std::cout<<twix.name()<<" "<<twix.price()<<" "<<twix.expired()<<std::endl; Snack mars=Snack("Mars",1.5,false); std::cout<<mars.name()<<" "<<mars.price()<<" "<<mars.expired()<<std::endl;…Complete C++ source code for Write a complete C++ program to help the manufacturer determine the greatest profit obtain from making tables and chairs with a given number of M type A and N type B wood blocks. • The program should prompt the user to input M and N.• Then tabulates all the combinations of tables and chairs possibly made, and calculates the profit obtain using array. • The program should also identify the greatest profit and make a concluding remark.• The program should be written in modular form with the main() function calling other functions. If arrays are involved in the function, the arrays should be passed into the function as parameters.• Lastly, display the output to an external .txt file.#include <bits/stdc++.h> using namespace std; struct Employee { string firstName; string lastName; int numOfHours; float hourlyRate; char major[2]; float amount; Employee* next; }; void printRecord(Employee* e) { cout << left << setw(10) << e->lastName << setw(10) << e->firstName << setw(12) << e->numOfHours << setw(12) << e->hourlyRate << setw(10) << e->amount << setw(9) << e->major[0]<< setw(7) << e->major[1]<<endl; } void appendNode(Employee*& head, Employee* newNode) { if (head == nullptr) { head = newNode; } else { Employee* current = head; while (current->next != nullptr) { current = current->next; } current->next = newNode; } } void displayLinkedList(Employee* head) { Employee* current = head; if(current!=nullptr){ cout…SEE MORE QUESTIONS