b.The molar heat capacity of white tin (Sn(white) Varies with temperature as follows: T/K 20 30 40 60 80 198 249 274 289 Cp.m/JKT 1.970 5.460 9.387 15.33 19.49 26.17 26.71 26.84 26.88 Calculate AG from grey/white tin transformation at 298 K [Given: S29(Sa(grey) = 38.77 J K AH Sa(grey) Sn(white) = 2234 J]

b.The molar heat capacity of white tin (Sn(white) Varies with temperature as follows: T/K 20 30 40 60 80 198 249 274 289 Cp.m/JKT 1.970 5.460 9.387 15.33 19.49 26.17 26.71 26.84 26.88 Calculate AG from grey/white tin transformation at 298 K [Given: S29(Sa(grey) = 38.77 J K AH Sa(grey) Sn(white) = 2234 J]

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter2: The First Law Of Thermodynamics

Section: Chapter Questions

Problem 2.46E: Define isobaric,isochoric, isenthalpic,and isothermal. Can achangein a gaseous system be isobaric,...

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A novel inorganic compound has two different crystalline forms, namely blue and red crystals. The physical and thermodynamic properties of blue and red crystals are given below. Mw of the novel inorganic compound is 86.54 g mol1. Properties (T = 298 K, P = 1.00 bar) Blue Red AH; (kJ mol 1) -1722.6 -1722.9 AG (KJ mol 1) -1648.5 -1647.1 Sin (U K1 mol 1) 86.4 81.2 CPm (JK1 mol 1) 66.5 65.7 Density (g mL 1) 2.145 2.278 What pressure must be achieved to induce the conversion of blue to red crystal at T = 298 K? Assume both blue and red crystals are incompressible at T = 298 K. Answer in bar to 0 decimal place (e.g. 1762)
The molar heat capacity of white tin (Sn(white)) varies with temperature as follows:T/K 20 30 40 60 80 198 249 274 289 Cp,m/JK-1 1.970 5.460 9.387 15.33 19.49 26.17 26.71 26.84 26.88Calculate change in G from grey/white tin transformation at 298 K [Given: S298(Sn(grey) = 38.77 J K-1 ΔH(Sn(grey) →Sn(white) = 2234 J]
b.The molar heat capacity of white tin (Sngwhite)) Varies with temperature as follows: 80 T/K 20 |Ca/JK" | 30 | 40 60 198 249 274 289 1.970 | 5.460| 9.387 | 15.33 | 19.49 | 26.17 | 26.71 26.84 26.88 Calculate AG from grey/white tin transformation at 298 K [Given: S3s6agrwy) = 38.77 J K' AH(s«pey) →s«nh#e) = 2234 J]
The molar heat capacity of white tin (Sn(white)) varies with temperature as follows: 20 30 40 60 80 198 249 274 289 1.970 5.460 9.387 15.33 19.49 26.17 26.71 26.84 26.88 Calculate ΔG from grey/white tin transformation at 298 K[Given: S298(Sn(grey) = 38.77 J K-1ΔH(Sn(grey) →Sn(white) = 2234 J]
Suppose that 6.0 mmol of perfect gas molecules initially occupies 52 cm3 at 298 K and then expands isothermally to 122 cm3. Calculate ΔG for the process.
1.65 mol of a perfect gas for which Cv,m = 12.47 J K–1 mol–1 is subjected to two successive changes in state: (1) from 37.0 oC and 1.00´105 Pa, the gas is expended isothermally against a constant pressure of 16.5´103 Pa to twice its initial volume. (2) At the end of the previous process, the gas is cooled at constant volume from 37.0 oC to - 23.0 oC. (a) Calculate q , w , DU, DH for each of the stages.
The molar heat capacity (C. (T)) for iron is given by the following Shomate equation, and 3. P,m is valid between 298-700 K, 0.012643 C (T)=|18.42+24.647 – 8.9147² +9 +9.6657³. J mol K Calculate AH when heating 1 g of Fe from 200-250°C.
11, .A Carnot heat engine contains 8.00 moles of oxygen gas (assume Cv.m= 2.5R). The temperature of the heat source is 500.0 °C and the temperature of the cold reservoir is 25.0 °C. Calculate the thermodynamic efficiency, V₁, V2, V3, V4, P3, P4, w and q for each step of the cycle and the total heat and work of the cycle if P1 = 20.0 bar and P₂ = 5.00 bar.
b.The molar heat capacity of white tin (Snwhite) Varies with temperature as follows: 30 40 60 | 5.460 9.387 | 15.33 | 19.49 26.17 26.71 T/K 20 80 198 249 274 289 Cam/JK" 1.970 26.84 26.88 Calculate AG from grey/white tin transformation at 298 K (Given: Sywsm pry = 38.77 J K' AHsaey) Satwhae) = 2234 J]
The standard entropies at 298 K for certain group 4A elementsare: C(s, diamond) = 2.43 J/mol-K, Si1s2 = 18.81 J/mol-K, Ge1s2 = 31.09 J/mol-K, and Sn1s2 = 51.818 J/mol-K. All but Sn have the same (diamond) structure. Howdo you account for the trend in the S° values?
a chemist carefully measure the amount of heat needed to raise the temperature of a 0.60 kg sample of a pure substance from 47.3 c tp 53.3c. the experiment shows that 15. kj of heat are needed. what can the chemist report for the specific heat capacity of the substance? round to 2 sig figs.
The molar heat capacity of white tin (Sn(white)) varies with temperature as follows: T/K 20 30 40 60 80 198 249 274 289 Cp,m/JK-1 1.970 5.460 9.387 15.33 19.49 26.17 26.71 26.84 26.88 Calculate ∆G from grey/white tin transformation at 298K [Given: S298(Sn(grey))=38.77JK-1 ∆H(Sn(grey))»Sn(white)=2234J ]