b. Which would have the greatest number of hydrogen peroxide molecules: 50.0 ml of a 3.00%w/v solution of hydrogen peroxide, OR 100.0 ml of a 10.0 mM solution of hydrogen peroxide,or a solution of hydrogen peroxide made by adding 25.0 ml of 2.5 M hydrogen peroxide andtopping it off with water to a total volume of 1 L? Show all of your work.

Answered: b. Which would have the greatest number…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter3: Chemical Reactions

Section: Chapter Questions

Problem 86QRT

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b. Which would have the greatest number of hydrogen peroxide molecules: 50.0 ml of a 3.00%
w/v solution of hydrogen peroxide, OR 100.0 ml of a 10.0 mM solution of hydrogen peroxide,
or a solution of hydrogen peroxide made by adding 25.0 ml of 2.5 M hydrogen peroxide and
topping it off with water to a total volume of 1 L? Show all of your work.

Expert Solution

Step 1

w/v% is defined as the amount of solute present per 100mL of solution. It is given by

$w / v % = \frac{M a s s o f s o l u t e}{V o l u m e o f s o l u t i o n} \times 100 %$

Step 2

We need to find that which solution of hydrogen peroxide will have higher number of molecules, we know, if a solution has higher of moles, we can say that, that solution will have the higher of molecules. So, we need to find the moles of hydrogen peroxide in each solution.

a) 50.0mL of 3% w/v

$\begin{array}{rcl} w / v % & = & \frac{M a s s o f h y d r o g e n p e r o x i d e}{V o l u m e o f s o l u t i o n} \times 100 % \\ 3 % & = & \frac{M a s s o f h y d r o g e n p e r o x i d e}{50 m L} \times 100 % \\ M a s s o f h y d r o g e n & = & \frac{3 % \times 50 m L}{100 %} \\ = & 1.5 g \\ M o l a r m a s s o f H_{2} O_{2} & = & 34 g / m o l \\ M o l e s o f H_{2} O_{2} & = & \frac{M a s s o f H_{2} O_{2}}{M o l a r m a s s} \\ = & \frac{1.5 g}{34 g / m o l} \\ = & 0.044 m o l e s \end{array}$

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