b. What if a breeder were working with 7 different, independently segregating genes, as Mendel did? How many generations would it take him to have pure-breeding varieties, starting from an F1 hybrid that is heterozygous for all 7 genes? i. What is the probability that an individual in the F2 generation would be pure-breeding (i.e. is homozygous at all 7 loci)? [Hint: this is an “and” calculation since it must be homozygous at each of the 7 loci. ii. What is the probability that an individual in the F3 generation would be pure-breeding? iii. What is the probability that an individual in the F10 generation would be pure-breeding?

b. What if a breeder were working with 7 different, independently segregating genes, as Mendel did? How many generations would it take him to have pure-breeding varieties, starting from an F1 hybrid that is heterozygous for all 7 genes? i. What is the probability that an individual in the F2 generation would be pure-breeding (i.e. is homozygous at all 7 loci)? [Hint: this is an “and” calculation since it must be homozygous at each of the 7 loci. ii. What is the probability that an individual in the F3 generation would be pure-breeding? iii. What is the probability that an individual in the F10 generation would be pure-breeding?

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter18: Genetics Of Behavior

Section: Chapter Questions

Problem 14QP: A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known...

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BIU A- == 三E 12 - Match each of the following examples to the appropriate type of non-Mendelian inheritance. 1. A homozygous recessive genotype for the gene that encodes phenylalanine hydroxylase (which breaks down the amino acid phenylalanine) causes lighter skin color, a musty odor, differences in intellectual development, and seizures. 2. In pea plants, alleles of Gene W control flower color, with the dominant allele (W) leading to purple flower.color, and the recessive allele (w) leading to white flower color. Usually, a genotype of WW or Ww leads to purple flowers. However, when Gene C is homozygous recessive, WW or Ww plants always have white flowers. 3. In mallard ducks, feather coloring is controlled by Gene F. A dominant allele (F) leads to green head feathers, while a recessive allele (f) leads to brown head feathers. In male mallards, inheritance of one or more F alleles always leads to the green head feather trait. But female mallards always have brown head feathers,…
type P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONS
A. Select and assign symbols for the genes involved, and determine the genotypes of the parents and offspring in each cross. Pigeons may exhibit a checkered or plain color pattern. In a series of controlled matings, the following data were obtained. F1 Progeny P1 Cross Checkered Plain 1. (a) checkered x checkered 36 0 2. (b) checkered x plain 38 0 3. (c) plain x plain 0 35 Then F1 offspring were selectively mated with the following results. (The P1 cross giving rise to each F1 pigeon is indicated in parentheses.) F2 Progeny F1 x F1 Cross Checkered Plain 4. checkered (a) x plain (c) 34 0 5. checkered (b) x plain (c) 17 14 6. checkered (b) x checkered (b) 28 9 7. checkered (a) x checkered (b) 39 0
. In a dihybrid test cross, the following results were obtained: A‑B‑, 121; A‑bb, 107; aaB-, 115; and aabb, 93. Do these data approximate a dihybrid test cross ratio with independent assortment? Complete the following table and answer the related questions. Phenotype O E (O-E) (O-E)2 (O-E)2/E A_B_ 121 A_bb 107 aaB_ 115 aabb 93 Totals X2= Instructor’s Calculation of X2= 4.0367 In interpreting this X2 value, you have ____3_______degrees of freedom. In this case do you accept/reject the hypothesis that these data approximate a dihybrid test cross ratio with independent assortment? What is the probability that the deviations are due to chance alone?
a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…
A. What is the inheritance pattern of the pedigree illustrated above? Explain in 1 sentence minimum citing two pieces of evidence from the pedigree to support your answer. B. Assuming that the disorder portrayed in this pedigree is very rare, based on your answer in a., what are the most likely genotypes of I-2, Ill-7 and I1-3. C. Based on your answer in a, what are the odds that IV-1 and IV-2 would have an affected male child?
A is dominant over a and B is dominant over b. Genes A/a and B/b assort independently. The parental cross (P) is between true- breeding (homozygous) strains (AA bb x aa BB). The resulting F1 offspring would be [Select ] A F1 x F1 cross gives the F2 generation. The ratio of phenotypes in the F2 generation can be described as [ Select ] In the phenotypic ratio, what number refers to individuals that are: dominant for both traits? [ Select ] recessive for both traits? [Select ] To what phenotypes do the "3"s in the ratio refer? [ Select ] > >
Purple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口ロ口

Mendelian Genetics [6F.R]:Question 1 In rabbits, grey fur (G) is dominant to white fur (g) and black eyes (B) are dominant to red eyes (b). A male rabbit with the genotype GgBb is crossed with a female rabbit with the genotype ggbb. What percent of the offspring will have white fur and red eyes? Select one: 25% 50% 100% 0% 1000
As attached, is a pedigree related question. I have a question, is it correct that individual I 1 's phenotype is Ff (heterozygous) whereas individual I 2 is ff (recessive homozygous)? That would mean that the ratio of Widow's Peak: Straight hair(no widow's peak) would be 1:1 ? So the chances of getting a Widow's Peak is 50% ? Is this correct? Am I doing it right.
A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?
Notation: D = disease allele at gene d = wild-type allele at gene Let’s provide some information about each MOI. AD: Each of the F1 parents is heterozygous for the D allele. SLR: The observed F2 data are the offspring from an F1 cross where the father is affected (disease) and the mother is an unaffected carrier (wild-type, or WT). That is, the mother’s genotype has one disease allele and one WT allele in it. In Table 1, I provide the observed data counts (in dark blue). Notice that I stratify by gender. Table 1 Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 Disease, Female 267 WT, Male 285 WT, Female 301 Total 1157 DF p-value In Table 2, provide expected proportions for two different MOIs: AD and SLR. The values in this table are computed using information from the Punnett Square and the specified MOI. Once the proportions are determined, we can fill in the values in Table 3, E(xpected)…