b. If the order of the stack input stream "30,60,56,44,98" What is the output if we execute the following operation SSUUSSSUSU? justify the answer? in ts
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- Given a stack of objects of type char, write the output and the stack contents atthe return of each function call. The stack is initially empty. (Assume pop() doesn’t return anything).Use stacks to implement a postfix-to-infix translator. Until the user closes the programme, it should continually read a postfix expression and output the identical infix expression. If the postfix expression entered is incorrect, throw an exception.use javaGiven a stack myData: Tom, Sam (top is Tom), what is the output after the following operations? Push(myData, Hal)Pop(myData)Pop(myData)Pop(myData)print(Pop(myData)) Group of answer choices Hal Sam Tom null
- Don't use inbuilt stack and provide codes for .cpp and .h Please provide a clear codes and output. Need ASAP. Thank you!What happens if the base condition is not defined in recursion ? a. Stack underflow b. Stack Overflow c. None of these d. Both a and bSuppose that we are asked to run the program and when our program reaches to line 23, weare also asked to take a snapshot of our program’s run-time stack. So, please draw full ARIsof the all subprograms which are placed in the stack at line 23.
- Implement an postfix-to-infix translator using stacks. The applicationshould repeatedly read a postfix expression and print the equivalentinfix expression until the user quits. Throw an exception if the postfixexpression entered is invalid.We have to hold information that's expressed inside parentheses while scanning to find the closing')'. We also have to hold information on operations that are of lower precedence on the stack.The algorithms are:a. Create an empty stack and an empty postfix and prefix output string/stream.b. Scan the infix input string/stream left to right.c. If the current input token is an operand, simply append it to the output string.d. If the current input token is an operator, push the operator onto the stack. Pop off operatorsthat have equal or higher precedence and append them to the output string;.e. The order of popping is the order in the output. If the current input token is '(', push it ontothe stack If the current input token is ')', pop off all operators and append them to theoutput string until a '(' is popped; discard the '('. If the end of the input string is found, popall operators and append them to the output string.This algorithm doesn't handle errors in the input, although careful…Use the C++ Standard Template Library's stack class to write a program for processing a file of postfix expressions. Recall that in a postfix expression, a binary operator comes after its two operands. Thus the infix expression (w +x) * (v-2) becomes wx+ys-* in postfix. A postfix expression can be efficiently evaluated using a stack as follows. 1. Read the expression from the left to the right. 2. When an operand is encountered, push it on the stack. 3. When an operator is encountered, pop the top two elements from the stack, perform the operation, and then push the result. 4. There should be exactly one element on the stack at the end and this element is the value of the еxpression. For example, if the expression 20 5 - 3 * is entered, the evaluation should proceed as follows. Symbol read Actions taken 20 Push 20 5 Push 5 Pop 5, Pop 20, Push 20 - 5 Push 3 3 Pop 3, Pop 15, Push 15 * 3 The result of 45 should then be output. Your program should ask the user for the name of an input…
- Implement a stack and solutions to the following problems: balancing parenthesis, evaluating postfix expressions and transforming infix expressions into postfix expressions. We are providing some sample code and input files: public/ balancing.cpp - main method to check whether an expression is balanced infix2postfix.cpp - main method to transform an infix expression into postfix input_balanced.txt - test cases for balancing.cpp input_infix2postfix.txt - test cases for infixtopostfix.cpp input_postfixEval.txt - test cases for postfixEval.cpp postfixEval.cpp - main method to evaluate postfix expressions stack.cpp - stack implementation stack.hpp - stack header file • To compile, run $ g++ stack.cpp balancing.cpp $ g++ stack.cpp postfixEval.cpp $ g++ stack.cpp infixtopostfix.cpp • To run each program, run $ ./a.out • The test cases follow this format: expected_solution input. Given input, your job is to implement code that gets the…Use the C++ Standard Template Library's stack class to write a program for processing a file of postfix expressions. Recall that in a postfix expression, a binary operator comes after its two operands. Thus the infix expression (w + x) * (y – z) becomes w x + y z * in postfix. A postfix expression can be efficiently evaluated using a stack as follows. 1. Read the expression from the left to the right. 2. When an operand is encountered, push it on the stack. 3. When an operator is encountered, pop the top two elements from the stack, perform the operation, and then push the result. 4. There should be exactly one element on the stack at the end and this element is the value of the expression. For example, if the expression 20 5 – 3 * is entered, the evaluation should proceed as follows. Symbol read 20 Actions taken Push 20 5 Push 5 Pop 5, Pop 20, Push 20 – 5 Push 3 Pop 3, Pop 15, Push 15 * 3 The result of 45 should then be output. Your program should ask the user for the name of an input…Could you please clarify the difference between the limited version of the stack and the unbounded version of the stack?