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- grammarly-G X * Content oard.odu.edu/ultra/courses/_393452_1/cl/outline F2 Question Completion Status: X GA student wan X 1 QUESTION 3 A student wants to determine the solubility of water and copper (1) bromide (a green solid) in ethyl acetate (a colorless organic liquid). She places 1 mL of ethyl acetate into each of two test tubes. To one, she adds 5 drops of water to it. To the other, she adds a small scoop of copper(1) bromide. 8.0 F3 2 - Which test tube represents the ethyl acetate and A. Test tube 1 copper(1) bromide if the copper(1) bromide is insoluble in ethyl B. Test tube 2 acetate? C. Test tube 3 D. Test tube 4 - Which test tube represents the mixture of the ethyl acetate and water if the water is insoluble in ethyl acetate? $ Question Com X C Chegg Search x 3 Which test tube represents the mixture of the ethyl acetate and water if the water is soluble in ethyl acetate? - Which test tube represents the ethyl acetate and copper(1) bromide if the copper(1) bromide is soluble…Q1\Asaturated solution of potassium chloride in 20c. Calculate %w\w and (M) concentration if it contains 298 g/L and D=1.17 g/cm Notice/ At.wt= K=39, Cl-35.5.1.5m 6A 200. mL solution that is 6.7 x 104 M in Cu²+ is mixed with 0.30 mole NH3. There is no change in volume as NH3 is bubbled in. What is the final [Cu]? Kf Cu(NH3)42 = 5.6 x 10¹¹ 124 . Kover= ksp kf 5." -9 Cu2++NH₂ CU(NH3) 4² 2+
- Calculated solely at 25 Celsius of PbCrO4 in pure water and in a .0130M. Na2CrO4 solution. Ksp of PbCrO4 is 2.8x10^-13A 22.41 mL of NaOH solution is required to reach the phenolphthalein endpoint in the standardization with 0.276 g of solid, monoprotic primary standard acid (MW 128.33) in a 25.00 mL solution. 12.34 mLof the same NaOH solution was added to titrate 5 mL of vinegar solution to the endpoint. Calculate the mass of acetic acid in this vinegar solution (d = 1.005 g/mL).FSC 8 1921. Brightspace A Aktiv Chemistry C D Z < Q + # At F2 @ 2 What volume in mL of 0.3000 M NaCl solution is required to produce 0.2700 moles of NaCl? W S app.101edu.co Walmart - Hiring Ce... X F3 X # 3 11. Unit 12: Late Adulthood - Develo X E JC 4 D F4 с 144 $ JU F5 R LL F ► 11 % 5 V F6 t 44 T G A 6 F7 Simulation play - Labster B Y H F8 & 7 8 U N Question 7 of 9 DELL F9 X D * 8 J F10 ( M Walmart - Hiring Center 9 F11 JI K 2 O ) O F12 L P 4 : 7 +/- PrtScr W 8 Insert { ( **
- 10-27. A 10.231-g sample of window cleaner containing ammonia was diluted with 39.466 g of water. Then 4.373 g of solution were titrated with 14.22 mL of 0.106 3 M HCl to reach a bromocresol green end point. (a) What fraction of the 10.231-g sample of window cleaner is contained in the 4.373 g that were analyzed? (b) How many grams of NH3 (FM 17.031) were in the 4.373-g sample? (c) Find the weight percent of NH3 in the cleaner.SCE students measured the concentration of HCl in a solution by titrating with different indicators to find the end point.Indicator Mean HCl concentration (M)(± standard deviation)Number of measurementsBromothymol blue 0.09565 ± 0.00225 28Methyl red 0.08686 ± 0.00098 18Bromocresol green 0.08641 ± 0.00113 29Is the difference between indicators 1 and 2 significant at the 95% confidence level? Answer the same question for indicators 2 and 3uo 9:04 docs.google.com a 154% O O Asiacell lI. Medical Chemistry Exam Super saturated solutions Darker color Lighter color Intermediate color Coulometric titrimetry: The time required to Consuming the analyte for the standard solution Fractionation the analyte for the standard solution Destroyed the analyte for the standard solution * Organic chemistry it deals with Living organismS
- 2- 150 mg of NazC2O4 containing solution is titrated with a KMNO4 solution with the corretion factor 1.03. The consumption of KMNO4 is found as 29 mL. Find the theoretical molarity (M) and real concentration (Mreal) of the KMNO4 solution.Q1\ Asaturated solution of potassium chloride in 20c. Calculate %w\w and (M) concentration if it contains 298 g/L and D=1.17g/cm Notice/ At.wt= K=39, Cl-35.5,Aspirin powder = 0.8110g MW of Aspirin = 180g.mol-1 Volume of 0.5N HCl consumed in back titration = 23.50mL Volume of 0.5N HCl consumed in blank titration = 44.50mL Percent purity (USP/NF) = Aspirin tablets contain NLT 90.0% and NMT 110.0% of the labeled amount of aspirin (C9H8O4) What is the calculated weight (in grams) of pure aspirin?..