b) => ⇒ Vallage across capacitor at t = 20/7 Ve (I msec) твес = 2005047 V 38ec Current through capacitar at Sc (Amber) msec = 0.720 80 -15x120 -15XI -0.36e t == T 80 -msec, (08 (30000 XII m) 180 Sin (30,000 × 17 m) x 80 ic (msec) -0.0316 A

Solve for the Vrms (magnitude only) across the capacitive reactance if R2 = 1082 ohms and Xc = 2328 ohms.

\ 35-\/5\ 50 25 75 357 */15 45 1st 40 +/15/+ Figure (3) 110 RIS

Q5/ Determine the Nodal Voltage for the figure 13 V₁ R3 ww 20 z 4A www 12 Ry 202 R₂602 ZA

Find out the error for the given program io = 1.7e-8; % dark saturation current in amperes tc = 27; % cell temperature in degree celsius isc = 250 ; % short circuit current density A/ square meter pin = 820; % solar radiation in w/square meter k =1.381e-23; % Boltzmann's gas constant e= 1.602e-19; % electronic charge t= 273+tc % cell temperature in Kelvin vmax=0.526; % mayi mum voltage in volts imax = (e*vmax)*(isc+io)/(k*t+e*vmax) pmax= vmax*imax efficiency = (pin/pmax)*100 O error in efficiency O no error O Error in pmax O Error in imax O no output

Datos: F1(KN)=5 F2(KN)=20 F3(KN)=10 L1(m)=4 H(m)=-5 I add the picture of the question

value of (m) = 9 value of (e) = 9 value of (ω) = 9   Value of LL = 9 Value of LR = 10

The Maclaurin expansion of f(x) = e-5* is (-1)"x" 5"n! n=0 as above. O None of these +00 (-1)"5"x" 57x" n! n! n3D0 レ

i li. * • J M 4 V:0r 团 / و امتحان ریاضيات.jpg Detetmine wethe the given lines ate patallel O1 per pendiculat, neither: a) y= 5x-2 and y=5x +3 りアー3y-6 and 3x +7• 14 O2/Gaph the foll ow ing functions: O y= 2 Sin LX FT)-1 のy-- SいくTメーT)+→ @3/ Find Hhe limiks far the following: X2 ズ→ III

ii) Calculate Vị and V2 (Give the answer in 2 decimal points). V = V2 :