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- 6:07 PM Wed Aug 4 * 63% learn-us-east-1-prod-fleet02-xythos.content.blackboardcdn.com + b My Questions |... Bb Homework – Or... Bb learn-us-east-1... Bb Presentations -... Bb Austin Commun... learn-us-east-1... Chem 2323 Org I Homework #18 H2O-I 1. What are the products and major product of each of the following reactions: а. hv + Cl2 b. hv + Cl2 с. hv HCI HBr hv + Нeat + NBS Peroxide. For the equilibriom 2CH4(G) 5SHC=CH@), fthe concentraHian of Ca Hy Ct equilbrium is 0.01375M, a whot Care the eqúli brium CancentrationS Of CHy and H2 7 b)Whatis the numencal vake of hc వివ్విUnder what conditions does the extended Debye-Huckel law, equation 8.52, become the Debye-Hckel limiting law?
- xwidevumaodecsrnocrmiocrvsntrclfmvrcxAMOICcinozcstbunvrlmxcmervor,tnivCCBSVI,dv,drvnkcnvunivrmrn binbo,bynlmrvtmiceucreivnebttnoevnejsfkdnxmvnfgkdjfkdgjksfjsnsfrgirog .1.If a dry gas is isothermally mixed with a liquid in a fixed volume, will the pressure remain constant with time? ans. No, explain. asnjcaericaqeonievtbcneivobuvntoigobnrcotuicnivvnrv1). The susceptibility of FeCl₂ obeys the Curie-Weiss law over the temperature range 90 K to room temperature (293K), with 0 =48K. Its molecular susceptibility at room temperature is 1.475 1022 emu/Oe g mol). (Use: N= 6.022 x 1023 atoms/g-mol, KB= 1.38 × 10-¹6 erg/K) (a) Show that the effective magnetic moment is 5.4 µB. (b) Show that the value of J is 2.25. (c) At an applied field of 8000 Oe, what is the value of the molecular field at 0 °C ?* © 38% ( 11:02 PM Mon Nov 22 te Homme Test Mustabow.al.stees and work to earn full.credit Name Michael zheng 1. Smplity tanetan y cot cot y Siny Extery C Cas Coas x). Cos tasr COsk /2 Anitial temp of m Inibial bempoewote 25°C nosz S.u0009 Tempulen mmestery motenl was burned Massof wa 66.29 WICA Tempur ert burnal 25780L Massof eter + burnced me tal 64,い00
- app.101edu.co erbilt Universit... M Inbox (2) - esmat.h... Lobby | Top Hat Aktiv Chemistry D2L Homepage - Vande... M Gmail Handshake VYES - Vanderbilt - S... Question 14 of 22 Aluminum nitrate forms a white crystalline hydrate with the formula AI(NO3)3 nH₂O(s). If this hydrate is heated to a high enough temperature, H₂O(g) can be driven off, leaving the anhydrous salt AI(NO3)3(S). A 15.152-gram sample of the hydrate was heated to drive off the water, leaving Al(NO3)3(s) with a mass of 8.603 grams. Calculate the value of n in Al(NO3)3.nH₂O(S). Course HomShow that CV,vib goes to nR as T ∞.You can use this as your reference: https://www.youtube.com/watch?v=2J2t5FRnMtM