automobile starter motor has an equivalent resistance of 0.0710 2 and is supplied by a 12.0-V battery with a 0.0320-2 internal resistance. (a) What is the current to the motor? 116.50 A (b) What voltage is applied to it? 8.2718 ✔ V (c) What power is supplied to the motor? 0.9636 kW (d) Repeat these calculations for when the battery connections are corroded and add 0.0900 to the circuit. (Significant problems are caused by even small amounts of unwanted resistance in low-voltage, high-current applications.) I= 12.3583 A V= P = 12.3958 x Check your calculations. V 153.1910 x Check your calculations. kW

automobile starter motor has an equivalent resistance of 0.0710 2 and is supplied by a 12.0-V battery with a 0.0320-2 internal resistance. (a) What is the current to the motor? 116.50 A (b) What voltage is applied to it? 8.2718 ✔ V (c) What power is supplied to the motor? 0.9636 kW (d) Repeat these calculations for when the battery connections are corroded and add 0.0900 to the circuit. (Significant problems are caused by even small amounts of unwanted resistance in low-voltage, high-current applications.) I= 12.3583 A V= P = 12.3958 x Check your calculations. V 153.1910 x Check your calculations. kW

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter17: Current And Resistance

Section: Chapter Questions

Problem 10CQ: Power P0 = I0 V0 is delivered to a resistor of resistance R0. If the resistance is doubled (Rnew =...

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Power P0 = I0 V0 is delivered to a resistor of resistance R0. If the resistance is doubled (Rnew = 2R0) while the voltage is adjusted such that the current is constant, what are the ratios (a) Pnew/P0 and (b) Vnew/V0? If, instead, the resistance is held constant while Pnew = 2P0, what are the ratios (c) Vnew/V0, and (d) Inew/I0?
Integrated Concepts (a) Assuming 95.0% efficiency for the conversion of electrical power by the motor, what current must the 12.0-V batteries of a 750-kg electric car be able to supply: (a) To accelerate from rest to 25.0 m/s in 1.00 min? (b) To climb a 2.00 102-m- high hill in 2.00 min at a constant 25.0-m/s speed while exerting 5.00 102 N of force to overcome air resistance and friction? (c) To travel at a constant 25.0-m/s speed, exerting a 5.00 102 N force to overcome air resistance and friction? See Figure 20.44.
Integrated Concepts (a) What energy is dissipated by a lightning bolt having a 20,000-A current, a voltage of 1.00102 MV, and a length of 1.00 ms? (b) What mass of tree sap could be raised from 18.0°C to its boiling point and then evaporated by this energy, assuming sap has the same thermal characteristics as water?
A child’s electronic toy is supplied by three 1.58-V alkaline cells having internal resistances of 0.0200 in series with a 1.53-V carbon-zinc dry cell having a 0.100- internal resistance. The load resistance is 10.0 . (a) Draw a circuit diagram of the toy and its batteries, (b) What current flows? (c) How much power is supplied to the load? (d) What is the internal resistance of the dry cell if it goes bad, resulting in only 0.500 W being supplied to the load?
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An automobile starter motor has an equivalent resistance of 0.075 Ω and is supplied by a 12.0 V battery that has a 0.015 Ω internal resistance. Part (a) What current, I, in amperes, does the battery supply to the motor? I = 133 Part (b) What is the terminal voltage, V, in volts, of the motor? V = 10.00 Part (c) What power, P, in kilowatts, does the motor consume? P = 1.6 for part c is incorrect.
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