I completed the problem but for some reason, my answer is still wrong. for part a I got 5.48 x 10^-5 and for part b I got 5.61x10^-4. I substituted the concentrations in the equation but hey still seem to be wrong can someone explain? At 25°C, the reaction, I(aq) + OCI (aq) → Ol(aq) + Cl(aq), has the following rate law:Rate (0.827 L mol¹ s¹) [I][OC].Calculate the rate of the reaction when:(a)[I] 0.0146 M and [OCI] = 0.0454 M: Rate = imol L-1 s-1(b)[I]=0.140 M and [OCI] = 0.0485 M: Rate=mol L-1 s-1

Answered: Image /qna-images/answer/ee3eedc2-8022-47fd-9791-c206452cbd65.jpg

At 25°C, the reaction, I(aq) + OCI (aq) → Ol(aq) + Cl(aq), has the following rate law: Rate (0.827 L mol¹ s¹) [I][OC]. Calculate the rate of the reaction when: (a) [I] 0.0146 M and [OCI] = 0.0454 M: Rate = i mol L-1 s-1 (b) [I]=0.140 M and [OCI] = 0.0485 M: Rate= mol L-1 s-1

At 25°C, the reaction, I(aq) + OCI (aq) → Ol(aq) + Cl(aq), has the following rate law: Rate (0.827 L mol¹ s¹) [I][OC]. Calculate the rate of the reaction when: (a) [I] 0.0146 M and [OCI] = 0.0454 M: Rate = i mol L-1 s-1 (b) [I]=0.140 M and [OCI] = 0.0485 M: Rate= mol L-1 s-1

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter11: Chemical Kinetics: Rates Of Reactions

Section: Chapter Questions

Problem 31QRT

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Question

I completed the problem but for some reason, my answer is still wrong. for part a I got 5.48 x 10^-5 and for part b I got 5.61x10^-4. I substituted the concentrations in the equation but hey still seem to be wrong can someone explain?

At 25°C, the reaction, I(aq) + OCI (aq) → Ol(aq) + Cl(aq), has the following rate law:
Rate (0.827 L mol¹ s¹) [I][OC].
Calculate the rate of the reaction when:
(a)
[I] 0.0146 M and [OCI] = 0.0454 M: Rate = i
mol L-1 s-1
(b)
[I]=0.140 M and [OCI] = 0.0485 M: Rate=
mol L-1 s-1

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