KAssume that 26.3% of people have sleepwalked. Assume that in a random sample of 1503 adults,435 have sleepwalked.a. Assuming that the rate of 26.3% is correct, find the probability that 435 or more of the 1503 adultshave sleepwalked.b. Is that result of 435 or more significantly high?c. What does the result suggest about the rate of 26.3%?e this6YHView an example Get more help.ox&Na. Assuming that the rate of 26.3% is correct, the probability that 435 or more of the 1503 adults havesleepwalked is(Round to four decimal places as needed.).4-7U*+008M(KV9O)OVC4Clear all=prt scpauseCheck answerbackspace40 Dlockenter5:53 PM10/20/2022homet shiftA

Solution-: Given: n=1503, P=0.263 We want to find, (a) P(435 or more of the 1503 adults have…

Assume that 26.3% of people have sleepwalked. Assume that in a random sample of 1503 adults, 435 have sleepwalked. a. Assuming that the rate of 26.3% is correct, find the probability that 435 or more of the 1503 adults have sleepwalked. b. Is that result of 435 or more significantly high? c. What does the result suggest about the rate of 26.3%?

Assume that 26.3% of people have sleepwalked. Assume that in a random sample of 1503 adults, 435 have sleepwalked. a. Assuming that the rate of 26.3% is correct, find the probability that 435 or more of the 1503 adults have sleepwalked. b. Is that result of 435 or more significantly high? c. What does the result suggest about the rate of 26.3%?

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter8: Sequences, Series,and Probability

Section: Chapter Questions

Problem 41CT: On a game show, a contestant is given the digits 3, 4, and 5 to arrange in the proper order to form...

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