Assume a fully associative cache with 4 lines. Assume that the initial state of the tags are Joe, Kim, Sue, and Meg respectively as shown below. Applying the LRU policy, complete the table below for the following tag address sequence: Joe -> Dan -> Sue You can complete the table by replacing labels noted from A through P. Note that the TAG will be the names and COUNT will be numbers. The first column "Joe" is completed for you as a reference. INITIAL TAG Joe Kim Sue Meg A= COUNT 0 1 2 3 Joe TAG Joe Kim Sue Meg B= COUNT 3 0 1 2 Dan TAG A C E G 1= COUNT B D F H Sue TAG I K Σο J= COUNT J L N za P

C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter13: Structures
Section13.5: Dynamic Data Structure Allocation
Problem 3E
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Assume a fully associative cache with 4 lines. Assume that the initial state of the tags are Joe,
Kim, Sue, and Meg respectively as shown below. Applying the LRU policy, complete the table
below for the following tag address sequence: Joe -> Dan -> Sue
You can complete the table by replacing labels noted from A through P. Note
that the TAG will be the names and COUNT will be numbers. The first column
"Joe" is completed for you as a reference.
INITIAL
TAG
Joe
Kim
Sue
Meg
A=
COUNT
0
1
2
3
Joe
TAG
Joe
Kim
Sue
Meg
B=
COUNT
3
0
1
2
Dan
TAG
A
с
E
G
|=
COUNT
B
D
F
H
Sue
TAG
I
K
M
O
J=
COUNT
J
L
N
P
Transcribed Image Text:Assume a fully associative cache with 4 lines. Assume that the initial state of the tags are Joe, Kim, Sue, and Meg respectively as shown below. Applying the LRU policy, complete the table below for the following tag address sequence: Joe -> Dan -> Sue You can complete the table by replacing labels noted from A through P. Note that the TAG will be the names and COUNT will be numbers. The first column "Joe" is completed for you as a reference. INITIAL TAG Joe Kim Sue Meg A= COUNT 0 1 2 3 Joe TAG Joe Kim Sue Meg B= COUNT 3 0 1 2 Dan TAG A с E G |= COUNT B D F H Sue TAG I K M O J= COUNT J L N P
C=
E=
G=
D=
F=
H=
K=
M=
0=
L=
N=
P=
Transcribed Image Text:C= E= G= D= F= H= K= M= 0= L= N= P=
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