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- Consider the molecule 1-bromo-2-methylbutane. C3 and C4 should be drawn as Et as in theexample. This group is called an ethyl group and can be considered a sphere about twice the sizeof a methyl group. Draw the following Newman projections sighting down the C1C2 bond... a. The lowest potential energy conformation. b. The highest potential energy staggered conformation.Build a model of methylcyclohexane, and use the model to complete the following Newmanprojections of methylcyclohexane in the chair conformation: a. When the methyl group is in an axial or equatorial (circle one) position, the molecule is inits lowest potential energy conformation. b. Label one Newman projection above anti and the other gauche to describe the relationshipbetween the methyl group and C3 of the ring. c. In general, which is a lower PE conformation, anti or gauche? d. Explain how your answer to b and c provide an explanation for why it is more favorable fora large group to be in an equatorial than an axial position.Assign the absolute configuration of all molecules. Draw the most stable conformer in Newman projects with respect to bond C2-C3; for both a) and b). Draw Fisher projections for all molecules.
- translate the bond-line notation structure to the Newman projection by filling int the missing groups (A, B, C, D or E) on the lines in the Newman projection so they match the conformation given in the original structure. Circle if the conformation is a staggered or eclipsed.We consider the following molecule A: And. THIS Of the following Newman projections, indicate: MeEt F F Me 1 Br 5 Br F And Me THIS CH2CH3 AT CH2CH3 "CH3 Br Br Me Me. THIS 2 Br 6 And And .And And Br CI Me F And 3 F And 7 Me the one that corresponds to the least stable conformation of molecule A: And Br And the one that corresponds to the most stable eclipsed conformation of molecule A: CI Me THIS And Br And Br F F And Me And Choose... Choose... the one that corresponds to molecule A as seen by the eye of the observer in the statement: Choose... the one that corresponds to the least stable staggered conformation of molecule A: the one that corresponds to the most stable conformation of molecule A: Choose... Choose... ◆a) Sighting along its C-N bond, draw the Newman projection of the conformation of dimethylamine given in perspective below. (Note the presence of the lone pair of electrons on the nitrogen.) H H C-N H CH3
- Which of the following is a Newman projection for the following compound as viewed down the indicated bond in the conformation shown? Save Et H. I CH3 Et CH3 CH3 CH3 Et H H. I Et CH3 -I || Et Da CH3 H CH3 Et I H₂ ||| CH3 H. I -I H CH3 H CH3 IV5.Draw the most stable conformer of each of the following ) Use Newman projections for straight chain compound and chair for cyclic compounds (а) 2,3-dimethylbutane (b) (c) .. |a) b) 4. Assign the absolute configuration of all molecules. Draw the most stable conformer in Newman projects with respect to bond C2-C3; for both a) and b). Draw Fisher projections for all molecules.. F H CI CI 2 2 2 3 CH3 3 3 CH3 CI H H configuration C2 configuration C3 tafa configuration C2 configuration C3 tale
- 6. Newman projections to Lewis structures From the following Newman projections, draw the corresponding Lewis structure in the same conformation. A) B) H. H CH3 H₂C N H OH CI Br CH3 H OH CH3, draw its and then in the 2. For (1R, 2S, 4R)-4-tert-buyl-1-ethyl-2-methylcyclohexane: draw its correct skeletal structure most stable conformer first showing the Hydrogens that are directly attached to the ring last stusture omit the hydrogens that are directly connected to the ring and draw the correct positions of the three alkyl groups in skeletal representation. Draw all bonds with the same length! 5. draw the correct skeletal structure here showing stereochemistry on this chair draw the most stable conformer including the H's directly attached to the ring on this chair draw only the alkyl groups, all bonds same lenghtDraw Newman projects of all the staggered conformations for the molecule below looking along the bolded bond in the direction indicated by the arrow. The carbon closest to the arrow should be the front carbon of your Newman projection. (It is a practice problem from the book but I am confused about how to approach it.)