Apply the Paint Blue algorithm discussed in class to the following Finite Automata. a a a b b a a + a b Show the status of the Finite Automata at the conclusion of the Paint Blue Algorithm (mark the visited states with an X and only include edges that have not been followed).
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- Correct answer will be upvoted else downvoted. Computer science. Michael is blamed for disregarding the social removing rules and making a danger of spreading Covid. He is currently shipped off jail. Fortunately, Michael knows precisely what the jail resembles from within, particularly since it's actual straightforward. The jail can be addressed as a square shape a×b which is separated into stomach muscle cells, each addressing a jail cell, normal sides being the dividers among cells, and sides on the border being the dividers prompting opportunity. Prior to condemning, Michael can ask his companions among the jail representatives to make (all around stowed away) openings in a portion of the dividers (counting dividers among cells and the furthest dividers). Michael needs to have the option to escape the jail after this, regardless of which cell he is set in. Be that as it may, he likewise needs to break as couple of dividers as could be expected. Your assignment is to…Design a deterministic finite state automaton (DFA) that accepts exactly the strings over the alphabet {A, B, ...,Z} that contain at least two R, at most one T, and where every E comes after some S (there may be other letters in between). For instance, your DFA should accept the strings: • MYSTICWARRIORS • MARSMATRIX • SHOCKTROOPERS • CONTRAHARDCORPS STRIDER but not the strings • CRAZYTAXI (it does not contain at least two Rs) LASTRESORT (it contains more than one T) AFTERBURNER (there are Es without a S somewhere before them) • BATTLECIRCUIT (all of these at the same time) Clearly indicate the meaning of each state. One way to do this is to number the states and have a numbered list of their meanings, but any readable method you use to label and explain your states is fine. Hint: there are three separate conditions accepted strings must meet; states will need to encode whether or not each one is met (or perhaps partially met). You can label an edge with the word “else" to indicate it…Artificial Intelligence programming assignment Here is the goal state and four start states for the 8-puzzle. Goal: Easy: Medium: Hard: Worst: 1 2 3 5 6 7 1 3 4 8 6 2 2 8 1 2 8 1 8 4 4 3 4 6 3 4 8. 76 5 7 7 6 5 7 5 3 2 1 Implement the following search algorithms and test them on the start states and goal state shown above. Only A* needs to detect duplicate states and eliminate them from the remainder of the search. 1. A* search using the heuristic function f*(n) = g(n) + h*(n), where h*(n) is the number of tiles out of place (not counting the blank). 2. A* search using the Manhattan heuristic function. 3. Iterative deepening A* with the Manhattan heuristic function. 4. Depth-first Branch and Bound with the Manhattan heuristic function. When defining the successor function, it is helpful to define the actions in terms of the empty tile, that is, the four actions are moving the empty tile right, down, left, and up. Consider the actions in this order in your implementation. If your…
- Convert the following DFA to an equivalent regular expression: Deterministic finite automaton a 93 a b b b a q2 q1 b a 44 Grafstate® M 1. Create an initial GNFA GO that is equivalent to M. Here are suggested steps: a. Choose a state in Q. Modify GO to create an equivalent GNFA called G1 that contains all states in GO except for the state you chose. b. Choose another state in Q. Modify G1 to create an equivalent GNFA called G2 that contains all states in G1 except for the state you chose. c. Choose another state in Q. Modify G2 to create an equivalent GNFA called G3 that contains all states in G2 except for the state you chose. d. Choose another state in Q. Modify G3 to create an equivalent GNFA called G4 that contains all states in G3 except for the state you chose.Correct answer will be upvoted else Multiple Downvoted. Computer science. one maneuver, the robot should move one cell to the left or right, given that it doesn't move beyond the field of play. As such, if the robot was in the cell I, it should move to either the cell i−1 or the cell i+1, as long as it lies among 1 and n (endpoints comprehensive). The cells, in the request they are visited (counting the cell the robot is set), together make a decent way. Every cell I has a worth computer based intelligence related with it. Let c0,c1,… ,ck be the succession of cells in a decent way in the request they are visited (c0 is the cell robot is at first positioned, c1 is the cell where the robot is after its first move, etc; all the more officially, ci is the cell that the robot is at after I moves). Then, at that point, the worth of the way is determined as ac0+ac1+⋯+ack. Your errand is to work out the amount of qualities over all conceivable great ways. Since this number can be…Using C++ Please add the specific explanation. Thanks. Huffman coding is used to compress data. The idea is straightforward: represent more commonlonger strings with shorter ones via a basic translation matrix. The translation matrix is easilycomputed from the data itself by counting and sorting by frequency.For example, in a well-known corpus used in Natural Language Processing called the "Brown"corpus (see nltk.org), the top-20 most frequent tokens, which are words or punctuation marksare listed below associated with frequency and code. The word "and" for example requireswriting three characters. However, if I encoded it differently, say, using the word "5" (yes, Icalled "5" a word on purpose), then I save having to write two extra characters! Note, the word"and" is so frequent, I save those two extra characters many times over!Token Frequency Codethe 62713 1, 58334 2. 49346 3of 36080 4and 27932 5to 25732 6a 21881 7in 19536 8that 10237 9is 10011 10was 9777 11for 8841 12`` 8837 13''…
- EXERCISE 6.4 Define the binary ↑ (Sheffer's stroke), and its dual as follows: x ↑ y10 :y x: 101 011 x + y10 : y 100 00 1 Show that {t} is expressively complete, and that so is {4}. (Hint: Express some expressively complete set using the connective.)Correct answer will be upvoted else downvoted. Computer science. You are given a grid a comprising of positive integers. It has n lines and m segments. Develop a framework b comprising of positive integers. It ought to have a similar size as a, and the accompanying conditions ought to be met: 1≤bi,j≤106; bi,j is a various of ai,j; the outright worth of the contrast between numbers in any nearby pair of cells (two cells that share a similar side) in b is equivalent to k4 for some integer k≥1 (k isn't really something similar for all sets, it is own for each pair). We can show that the appropriate response consistently exists. Input The primary line contains two integers n and m (2≤n,m≤500). Every one of the accompanying n lines contains m integers. The j-th integer in the I-th line is ai,j (1≤ai,j≤16). Output The output ought to contain n lines each containing m integers. The j-th integer in the I-th line ought to be bi,j.Correct answer will be upvoted else Multiple Downvoted. Computer science. You need to change this grouping so all components in it are equivalent (I. e. it contains a few events of a similar component). To accomplish this, you pick some integer x that happens to some extent once in a, and afterward play out the accompanying activity quite a few times (perhaps zero): pick some portion [l,r] of the arrangement and eliminate it. Yet, there is one special case: you are not permitted to pick a fragment that contains x. All the more officially, you pick some adjoining aftereffect [al,al+1,… ,ar] to such an extent that ai≠x if l≤i≤r, and eliminate it. After expulsion, the numbering of components to one side of the eliminated portion changes: the component that was the (r+1)- th is presently l-th, the component that was (r+2)- th is currently (l+1)- th, etc (I. e. the leftover arrangement simply falls). Note that you can not change x after you picked it. For instance, assume n=6,…
- define a java class and do the following Delete from list L1 nodes whose positions are to be found in an ordered list L2. For instance, if L1 = (A B C D E) and L2 = (2 4 8), then the second and the fourth nodes are to be deleted from list L1 (the eighth node does not exist), and after deletion, L1 = (A C E). Insert a node exactly in the middle of a singly linked list.Please help me Josephus Problem is a theoretical problem related to a certain counting-out game. On thiscase, people are standing in a circle waiting to be executed. After a specified number ofpeople are skipped, the next person is executed. The procedure is repeated with theremaining people, starting with the next person, going in the same direction and skippingthe same number of people, until one person remains, and is freed.Arrange the numbers 1 , 2, 3 , ... consecutively (say, clockwise) in a circle. Now removenumber 2 and proceed clockwise by removing every other number, among those thatremain, until one number is left. (a) Let denote the final number which remains. Find formula for .(b) If there are 70 people, what is the safe number (the number that remains)?A uwuified sentence is sentence that has been transformed using a made-up Internet language in which some of the letters in the words are replaced by something else. The exact scheme is described below: Any uppercase/lowercase R or L is replaced by w/w, respectively. • If we encounter an o/o in a word, check if the previous letter (if it exists) is an M/m or N/n. If the previous letter is one of these, insert the lowercase letter y in between them, regardless of the capitalization of the other letters. • All other characters are left unchanged. Some examples: Professor will be converted to Pwofessow (There are two r's that are replaced by w's. Since the two o's aren't proceeded by an M/n or N/n, no y will be inserted.) LLunoacyo will be converted to wwunyoacyo (The two L's will be replaced with two ws according to the first rule. Then the first o will have a y inserted in front of it between then and the o according to the second rule. The last o won't have a y inserted in between…