Ap Wg = 2000 N Wc= 2900 N Support tower -L = 30,5 m- SITUATION 02 Two gondolas on a ski lift are locked in the position shown in Fig. ESS4-TE-002 while repairs are being made elsewhere. The distance between support towers is L = 30.5 m. The lengths of each cable segment AB, BC, and CD under gondolas weighing 2 kN at B and 2.9 kN at C are 4.2 m, 21.2 m, and 5.8 m, respectively. The cable sag at B is A = 1.3 m and that at C is A = 2.4 m. Determine the tension (kN) in the cable BC.

Ap Wg = 2000 N Wc= 2900 N Support tower -L = 30,5 m- SITUATION 02 Two gondolas on a ski lift are locked in the position shown in Fig. ESS4-TE-002 while repairs are being made elsewhere. The distance between support towers is L = 30.5 m. The lengths of each cable segment AB, BC, and CD under gondolas weighing 2 kN at B and 2.9 kN at C are 4.2 m, 21.2 m, and 5.8 m, respectively. The cable sag at B is A = 1.3 m and that at C is A = 2.4 m. Determine the tension (kN) in the cable BC.

Residential Construction Academy: House Wiring (MindTap Course List)

5th Edition

ISBN:9781337402415

Author:Gregory W Fletcher

Publisher:Gregory W Fletcher

Chapter16: Video, Voice, And Data Wiring Installation

Section: Chapter Questions

Problem 2RQ

See similar textbooks

Similar questions

Question 2) (PA.3) If cable AD is tightened by a turnbuckle and develops a tension of 1300 lb, determine the tension developed in cables AB and AC and force developed along the antenna tower AE at point A. ( 30 ft A Non B 15 ft 12.5 ft 10 ft 15 ft
Problem 1.2 The top of a folding workbench has a mass of 50kg with mass center at G. A) Determine the resultant force in the pin at E B) Determine the force in cable FH 750 mm Go D 225 mm F H X E 1200 mm Check your work: Cable force, FFH = 1308 N B 900 mm
QUESTION 3) If tension in cable AB is 275 N and in cable AC is 450 N. Determine magnitude and direction of resultant of forces acting at A by two cables 24cm Z 40cm 12cm TAC -39cm- 18 C TAB 'Х
Given - Length of Cable PQ -25m Horizental distonce between Pa=20 m N Jom - Jo m Te Ta 8 53-13 53-13 36.8 12.5m 36-870 150KN Zet tension in cable PR and a R be Tp and l8 mespectivily Now in A P&R, Ps E RQ - 12'5 m' ニ PR = L PRS = ESR = sint( ) =53.13° 12.5 VSing lami's, theomem ,- Tp Sin (90+36.87) 150 Si'n(53.13+53.13 Sin(go+36'87) 150 xsin(90+36-87) Sin (53-13 + 5313). Tp - 124.98 KN Now we gst, the tension m the cable due to the applied load is > 125 KN い oitan of 2 12:5m
4G 4G ll 20:38 O O 54 Assignment 2 Each of the bodies shown is homogeneous and has a mass of 50 kg. Assume friction at all contact surfaces. Draw the fully dimensioned FBD for each body and determine the number of unknowns. Cable - 1.2 m -0.9 m 0.6 m Cable \30° 800 N/m 1.5 m 30 (0.1 m
e Quiz: Module 2 Quiz quizzes/332866/take/questions/4602488 10° A 60° C В If the maximum tension force the cable AB could carry is 1500 N before breaking, and the maximum compressive force the pole AC could carry is 2200 N before buckling, what is the maximum value of P in Newtons 97% 26°C Partly clou
4. The two cables shown carry a 100 N vertical load. A 3 A 100 N Most nearly, what is the tension in cable AB? (A) 40 N (B) 50 N (C) 60 N (D) 80 N
6 Ag Ac Wg = 2000 N Wc = 2900 N| Support tower -L = 30.5 m SITUATION 02 Two gondolas on a ski lift are locked in the position shown in Fig. ESS4-TE-002 while repairs are being made elsewhere. The distance between support towers is L = 30.5 m. The lengths of each cable segment AB, BC, and CD under gondolas weighing 2 kN at B and 2.9 kN at C are 4.2 m, 21.2 m, and 5.8 m, respectively. The cable sag at B is A = 1.3 m and that at C is A = 2.4 m. * Determine the minimum required effective cross-sectional area (mm^2) of the cables if the working stress is 100 MPa.
E 1.732 m C 1.732 m 3.0 m 3.0 m MA = 20kg The tension in the cable supporting the box is nearest to: 196.2kN 0.1962kN 0.01962N 1962000N O NONE OF THE GIVEN CHOICES
D Ag Ac Wg = 2000 N Support = 2900 N tower L = 30.5 m SITUATION 02 Two gondolas on a ski lift are locked in the position shown in Fig. ESS4-TE-002 while repairs are being made elsewhere. The distance between support towers is L = 30.5 m. The lengths of each cable segment AB, BC, and CD under gondolas weighing 2 kN at B and 2.9 kN at C are 4.2 m, 21.2 m, and 5.8 m, respectively. The cable sag at B is A = 1.3 m and that at Cis A = 2.4 m. * Determine the stress (MPa) in the cable BC if the effective cross-sectional area of the cables is 65 mm^2.
Cable Analysis : Analyze the loaded cables ac dhoon. TO0 m 10m tom 40 kg /m
Ex. Calculate tension in each segment of cable and vertical sag at B. 미 hs 2m- 3kN 2m 8KN -em* 2m