an "open system" is one in which mass cross its boundaries True False pV = mRT is made from the combination of 2 equations from? Boyle's and Charles' laws Charles' and Gay-Lussac's laws Boyle's and Gay-Lussac's laws It is defined as the quantity of heat required to change the temperature of unit mass through one degree. Heat transfer on Temperature difference Specific heat

an "open system" is one in which mass cross its boundaries True False pV = mRT is made from the combination of 2 equations from? Boyle's and Charles' laws Charles' and Gay-Lussac's laws Boyle's and Gay-Lussac's laws It is defined as the quantity of heat required to change the temperature of unit mass through one degree. Heat transfer on Temperature difference Specific heat

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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MATCH THE ANSWER WITH THE QUESTION Path Function Choose. Choose. Isobaric Process Pressure is constant Нeat Intensive property No work done Pressure Adiabatic Process Volume No transfer of heat
Jes 1:01 i docs.google.com/forms what is the Physicists recognize four fundamental forces.* Flectrical force O - Gravitational force -Strong nuclear force Weak nuclear force O -Muscular force Force of friction Ff is described by • Ff = µN * O p synovlal fluld in the Joints P -coefficient of fraction between two surface in The temperature of the human body is normally about 98.6°F.calculate the temperature of the body "C* oC = (5/9)x(oF-32) =5/9(98.6- 32)-37 oc oc=(9/5)x(of -32) =9/5(98,6-32) =13,3 Under resting conditions the body energy is being used as follows * O 27% by the liver and splee O 20-%by the skeletal musules Under resting conditions the body energy is being used as follows. O 19% by the brain. 15% by the kidney. We can write the first law of thermodynamics as: * O AU-AQ -A.. O AU-AQ +AW. 1kcal = J O 1 Kcal =4184j. O O O O
The topic of total derivation is mathematics
dated metncpdf Thermodynamics An Engineering X E Module2-chap2propertiesofpure x O File C:/Users/DANIEL/Desktop/300L%202ND%20SEMESTER%20MATERIALS/Module2-chap2propertiesofpuresubstances-130703012604 phpap. ID Page view A Read aloud V Draw H Highlight O Erase 40 MEC 451 - THERMODYNAMICS Faculty of Mechanical Engineering, UITM Supplementary Problems The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pressure gage reads 210 kRa. If the volume of the tire is 0.025 m3, Cetermine the pressure rise in the tire when the air temperature in the tire rises to 50°C. Also, determine the amount of air that must be bled off to restore pressure to its original value at this temperature. Assume the atmospheric pressure is 100 kPa. [ 26 kPa, 0.007 kg] 1. A 6 4 2:57 PM Lucky CORER 144 Tum lock 314 % 8 1/2 24 6 1/4 23 T K F pause B
This is for my thermodynamics chorus! Please consider degrees of freedom, the universal gas constant and the individual gas constant. Do not use PV=nRT for (c) Use another form of the ideal gas law to solve
An open system is often referred to as control volume, which is a properly selected region in space in which mass and energy can flow across the boundaries as figure 1.2. The boundary of a open thermodynamic system is called the control surface Across the Boundaries E = Yes F 0 = Yes w =Yes Control surface ass YES W CONTROL VOLUME energy YES Figure 1.2. A cooling/heating radiator is an example of such a system – give two more examples of such a system.
A random daily consisting of so electrical circuits Used to manufacture an ele ctrononic device for a periad of 20 daye, and a fter examining Them, the mumber of defective circuirts for each day wa as follows: meas urements X4 X2 Xs XS 1-04 1.01 o-981-021-00 2 1-02 0-97 0-96 1-01 \-02 3 1.01 1-07 0-99 1-031.00 46-98 0-97 1.02 0.98o.98 5 0-99 1-03 0-98 1-02|1.01 6 -02 0.9S|1-041.02 0o-95 71.00 0-991.01 1.02 1-ol 0.99 1-02 1-001.041-09 9 1.03 1-040-99 1-02 0-94 101.02 0-981.00 0.99 0.02 terms of the specific control a) for the mean and bi for the range 8
Give True or False for the following: 1.In liquids and gases, heat transmission is caused by conduction and convection 2.The surface geometry is the important factor in convection heat transfer 3. The heat transfer by conduction from heated surface to the adjacent layer of fluid, 4. The heat transfer is increased in the fin when &> 1 5.The unit of the thermal diffusivity is m²/s 6. Temperature change between the materials interfaces is attributed to the thermal contact resistance 7. A material that has a low heat capacity will have a large thermal diffusivity. 8. Heat conduction flowing from one side to other depends directly on thickness 9.Fin efficiency is the ratio of the fin heat dissipation with that of no fin 10.The critical radius is represented the ratio of the convicted heat transfer to the thermal conductivity
Conduction Heat Transfer X material (a) material (b) . both (a) and (b) have the same thermal conductivity the temperature distribution is independent of thermal conductivity it's not that simple 9. Fin efficiency is defined as: • tanh (mL) (hP/k Ac)1/2 (heat transfer with fin) / (heat transfer without fin) (actual heat transfer through fin) / (heat transfer assuming all fin is at T = Tb) (Tx=L-Tf)/(Tb-Tf) 10. For an infinite fin, the temperature distribution is given by: (T-Tf)/(Tb-Tf)= e-mx. The heat flow through the fin is therefore given by: k (Tb-Tf)/L ● zero, because the fin is infinite ● infinite because the fin is infinite ● (Tb-Tf) (hP/k Ac)1/2 ● (Tb – Tf) (h P / k Ac)1/2 tanh (mL) 11. The Biot number, Bi, is defined as: • Bi=hk/L • Bi=hL/k • Bi= k/LH • Bi=qL/k • Bi=p UL/k 12. For a plate of length L, thickness, t, and width, W, subjected to convection on the two faces of area L x W. What is the correct length scale for use in the Biot number? . L ● W ● t • t/2 • L/2 13. If Bi…
We performed the experiment to measure the thermal conductivity of 2 materials (Brass & Steel) in the laboratory and measured the following tabulated values: Material 1 - BRASS (Diameter = 25mm) Power Temperature (°C) Q' (W) 2 3 4 6 7 8 1 5 9 14.6 78.9 77.5 76 50.2 46.7 42.4 36.1 34.6 33.6 Material 2 - STEEL (Diameter = 25mm) Power Temperature (°C) 7 Q' (W) 14.25 2 3 1 9 88.6 87.4 85 34.1 33.4 32.7 CALCULATE THE FOLLOWING: MATERIAL 1 - BRASS Calculation for Brass Quantities Calculated Values Power (Q') W Area of cross section (A) m2 Difference in Temperature between two points (AT) °C Difference in distance between two points (Ax) m Thermal conductivity of brass (k,) W/m'C MATERIAL 2 - STEEL Calculation for Steel Quantities Calculated Values Power (Q') W Area of cross section (A) m? Difference in Temperature between two points (AT) "C Difference in distance between two points (Ax) m Thermal conductivity of steel (k,) W/m°C
According to the Newton's cooling law, the temperature of any substance is directly related to the distinction between the substance temperature and its environment (ambient) temperature dT =-k(T – T,)k(T-T) dt where Tis the substance temperature (C) T is the time (minute) k is constant T. is environmental temperature A casting ladle of molten metal has 290 °C, By using Euler methodology, evaluate the temperature from t=0 to 35 min with a step size of 2 min. If, T, is 25°C and k is 0,009/min.
Use for the ice? List all sumptions. 1.4 Consider axial flow of water in a cold tube. Write the heat conduction equation for the ice forming axisymmetrically on the inside surface of the tube. ice water 1.5 Consider two-dimensional conduction in the semi-circular cylinder shown. The cylinder is heated with uniform pe here to search 05:48 A qu) * ENG r-ny-E/-F hp